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3 years ago

2+x=15-7/8x how do you solve this?

Mathematics

1 answer:

uranmaximum [27]3 years ago

5 0

Answer:2+x=15-7/8x

We move all terms to the left:

2+x-(15-7/8x)=0

Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R

We add all the numbers together, and all the variables

x-(-7/8x+15)+2=0

We get rid of parentheses

x+7/8x-15+2=0

We multiply all the terms by the denominator

x*8x-15*8x+2*8x+7=0

Wy multiply elements

8x^2-120x+16x+7=0

We add all the numbers together, and all the variables

8x^2-104x+7=0

a = 8; b = -104; c = +7;

Δ = b2-4ac

Δ = -1042-4·8·7

Δ = 10592

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

The end solution:

Δ−−√=10592−−−−−√=16∗662−−−−−−−√=16−−√∗662−−−√=4662−−−√

x1=−b−Δ√2a=−(−104)−4662√2∗8=104−4662√16

x2=−b+Δ√2a=−(−104)+4662√2∗8=104+4662√16

Step-by-step explanation:

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Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

Line 1:

In line 1, the equation is given and is completely fine.

$y^{2}+8xy+2y+16x=0$

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

Line 2:

In line 2, the terms are grouped, from which we can factor out common terms.

$(y^{2}+8xy)+(2y+16x)=0$

This is also fine.

Line 3:

In line 3, the common term y is taken out from group 1 and 2 from other group.

$y(y+8x)+2(y+8x)=0$

which is exactly what is given in line 3.

Line 4:

In line 4 the common factors can be seen and easily split into 2 factors.

$(y+2)(y+8x)=0$

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

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3 years ago