Answer:
The answer is C.
Step-by-step explanation:
Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.
So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.
After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.
So, the correct match is option C ) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.
The expected number of heads seen in 12 flips is 8 heads seen
Step-by-step explanation:
We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.
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The speed of the Elvira is 6.545 miles per hour. Then the speed of the Altheia will be 0.545 miles per hour.
<h3>What is speed?</h3>
The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula
Speed = Distance/Time
Let the speed of the Elvira be x. Then the speed of the Altheia will be (x - 6).
Let the distance between the coffee shop and Elvira's house be d.
Then the distance between the coffee shop and Altheia's house will be (3.6 - d).
Then we have
x = d / 0.5 ...1
(x - 6) = (3.6 - d) / 0.6 ...2
In solving the equations 1 and 2, we have
x = 6.545 and d = 3.2725 miles
Then the speed of the Elvira is 6.545 miles per hour. Then the speed of the Altheia will be 0.545 miles per hour.
More about the speed link is given below.
brainly.com/question/7359669
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