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Brut [27]
3 years ago
13

Customers exiting a bottleneck form a Poisson process with a stationary flow of 400 per hour. What is the expected amount of tim

e needed to observe one customer's (exit) headway that is larger than five times the mean headway
Business
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

Customer's (exit) = 0.03 minutes per person

Explanation:

Given:

Flow (Ф) = 400 per hour

Times = 5 times headway

Computation:

5 times Poisson Distribution = 400 per hour × 5 time

5 times Poisson Distribution = 2,000 persons

Computation of expected amount of time needed to observe one customer :

Customer's (exit) = 1 hour / 2,000 persons

Customer's (exit) = 60 minutes / 2,000 persons

Customer's (exit) = 0.03 minutes per person

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Explanation:

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In the same vein, the maximum therefore that they would be willing to pay for the Western Division should be $78.25 as well because anything higher than that would constitute an Opportunity Cost loss.

They should go for the cheaper option and if buying from the Western Division exceeds the $78.25 then it is loss on their part. Western Division should charge the same or less.

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When building a new residential development or mall, a national real estate organization typically does not remove many trees, b
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3 years ago
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Giorgio Italian Market bought $4,000 worth of merchandise from Food Suppliers and signed a 90-day, 6% promissory note for the $4
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Answer:

B. Debit Notes Receivable $4,000; credit Sales $4,000

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Consider a project with free cash flows in one year of $90,000 in a weak economy or $117,000 in a strong economy, with each outc
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Answer:

B) $90,000

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x = the present value of cash flow for each outcome which is $90,000 in case of weak economy and $117,000 in case of strong economy.

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