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2 years ago

6

7 MORE picture below

2 answers:

Tema [17]2 years ago

8 0

Answer:

thats a acute angle witch is 62

Step-by-step explanation:

gladu [14]2 years ago

7 0

Answer:

65

Step-by-step explanation:

angles x and 25 are both Complementary, meaning they are on a right angle. So 90 minus 25 = x

90-25=65

x=65

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BRAINLIESTTT. ASAP! PLEASE HELP ME :)

Vsevolod [243]

Answer: Choice A

$\frac{\sqrt{6}+\sqrt{2}}{4}$

========================================================

Work Shown:

$\cos(30) = \frac{\sqrt{3}}{2}$

$\cos(\frac{x}{2}) = \sqrt{\frac{1+\cos(x)}{2}$

$\cos(\frac{30}{2}) = \sqrt{\frac{1+\cos(30)}{2}$

$\cos(15) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}$

$\cos(15) = \sqrt{\frac{\frac{2}{2}+\frac{\sqrt{3}}{2}}{2}$

$\cos(15) = \sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}$

$\cos(15) = \sqrt{\frac{2+\sqrt{3}}{4}}$

$\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

$\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{2}$

$\cos(15) = \frac{0.5\sqrt{6}+0.5\sqrt{2}}{2}$

$\cos(15) = \frac{\sqrt{6}+\sqrt{2}}{4}$

5 0

3 years ago

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Free_Kalibri [48]

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

Step-by-step explanation:

Given

$\left(x_1,\:y_1\right)=\left(-5,5\right)$

$m=\frac{-8}{5}$

Point-Slope Form equation is

$\left(y-y_1\right)=m\left(x-x_1\right)$

$\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$y-5=\frac{-8}{5}\left(x+5\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y-5=-\frac{8}{5}\left(x+5\right)$

$y-5+5=-\frac{8}{5}\left(x+5\right)+5$

$y=-\frac{8}{5}x-3$

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

5 0

3 years ago

1 5⁄7 ÷ 4 2⁄7 i need the anser im stuck

leonid [27]

15/7 divides by 42/7 equals 357/1000 or .357

4 0

3 years ago

Read 2 more answers

AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

$m=\frac{5}{7}$

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

$\Rightarrow m_1\times m_2 =-1$

$\Rightarrow \frac{5}{7}\times m_2 =-1$

$\Rightarrow m_2 = \frac{-7}{5}$

So, Slope for line BC : $m_2 = \frac{-7}{5}$

Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

$7x+5y-48=0$

Hence the equation of line BC : $7x+5y-48=0$

5 0

2 years ago

Six less than the quotient of a number and 4 is 15.

Artist 52 [7]

Answer:6 ÷ 4x = 15

Step-by-step explanation:

six is less than the quotient and quotient mean division, replace a number with a variable and put it with four and the you would put equal 15

8 0

3 years ago

Read 2 more answers