Question

3(t-7) =6. Solve for the and show steps

Answer 1

 $3(t -7) = 6 \\ 3(t) + 3(-7)\\ 3(-7) = -21 \\ 3t = 3t \\ 3t - 21 = 6 \\Add21: 3t - 21 + 21 = 6 +21 \\ 3t = 21: Divide3 \\ \frac{3t}{3} cancel = \frac{27}{3}keep \\ t = 9$
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 $8(h - 9) = 8 \\ 8h - 9 = 9 \\ 8h = 8h \\ 8(-9) = -72\\ 8h + (-72) = \\ 8h - 72 = 8 \\ Add72: 8h - 72 + 72 \\ = 8 + 72 \\ divide8 : \frac{8h}{8}cancel = \frac{80}{8} (keep) \\ h = 10$
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 $9 + 2(z - 2) = 15 \\ 9+2(z)+ 2(-2)= 15 \\ 2(-2) = -4 \\ 9 +2z = ? \\ 9 +2z+4 = 15\\ Subtract5: 2z + 5 -5 \\ = 15 -5 \\ Divide2: 2z = 10 \\ \frac{2z}{2}cancel = \frac{10}{2} = 5 \\ z = 5$
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