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kaheart [24]
3 years ago
9

What is the simplest from for 12/36

Mathematics
2 answers:
Bumek [7]3 years ago
4 0

1/3 just took the test

Stolb23 [73]3 years ago
3 0

1/3

Explanation:

12/12=1

36/12=3

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A. -4,0,2<br> B. -2,0,4<br> C. -5,0,17<br> D. -17,0,5
Lostsunrise [7]

Answer:

You have three

-4,0, and 2 or the answer choice A

Step-by-step explanation:

3 0
3 years ago
What are the benefits if you pay off all your high-interest debt such as credit cards and store cards?
jekas [21]

Answer:  The law required that 100% of your payment go toward your most expensive debt. ... The excess payment is everything you pay above the minimum. The Card Act requires issuers to apply this part of your payment to the highest-interest balance first.

6 0
3 years ago
What is the area of the composite shape?
Lelu [443]

Answer:

84 sq. inches

Step-by-step explanation:

When you section off each, you can find the area of each shape and add together to make composite.

Triangle on left is 6 sq. inches

Rectangle on right (5x10) is 50 sq. inches

Rectangle on bottom (7x4) is 28 sq. inches

3 0
3 years ago
A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
3 years ago
PLEASE HELP 35 POINTS!!!
lawyer [7]

Answer:

circle = square =5.53

Step-by-step explanation:   .

6 0
3 years ago
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