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Doss [256]
3 years ago
9

2 1 /4 meters by 1 7 /8

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

(\frac{9}{4} )(\frac{15}{8} )

\frac{135}{32}

=4\frac{7}{32}

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Evaluate 3^2 + (5-2) X 4 - 6/3
muminat

Answer:

The result is 19

Step-by-step explanation:

3^{2}  + (5-2)x4 - 6/3

Step 1: Parenthesizing (5-2)=3

3^{2}  + 3x4 - 6/3

Step 2: Exponentiation 3^{2}=9

9  + 3x4 - 6/3

Step 3: Multiplication and division 3x4=12 and 6/3=2

9  + 12 - 2

Step 4: Addition and subtraction 9+12=21, and 21-2=19

21-2

19

The operations are ordered from highest to lowest in the order:

1. Parenthesizing,

2. Factorial,

3. Exponentiation,

4. Multiplication and division,

5. Addition and subtraction.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Match the exponential expression with its rule:
mina [271]
1.=d 
2.=a
5.=b
4.=e
3.=c
6 0
4 years ago
You have 42 ft. of fencing (1 ft. segments) to make a rectangular garden. How much should each side be to maximize your total ar
Verizon [17]

Answer:

Length=10.5\ ft

Width=10.5\ ft

Area=110.25\ ft^{2}

Step-by-step explanation:

Let

x----> the length of the rectangular garden

y---> the width of the rectangular garden

we know that

The perimeter of the rectangle is equal to

P=2(x+y)

we have

P=42\ ft

so

42=2(x+y)

simplify

21=(x+y)

y=21-x------> equation A

Remember that the area of rectangle is equal to

A=xy ----> equation B

substitute equation A in equation B

A=x(21-x)

A=21x-x^{2}----> this is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex is the maximum area

The x-coordinate of the vertex is the length side of the rectangle that maximize the area

using a graphing tool

The vertex is the point (10.5,110.25)

see the attached figure

so

x=10.5\ ft

Find the value of y

y=21-10.5=10.5\ ft

The garden is a square

the area is equal to

A=(10.5)(10.5)=110.25\ ft^{2} ----> is equal to the y-coordinate of the vertex is correct

6 0
3 years ago
Based only on the given information, it is guaranteed that AB L CDGiven AABCAD BDBCCDs CDA. True
serious [3.7K]
Hello,

any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|


7 0
3 years ago
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Can someone please help me with this?
Norma-Jean [14]

Answer:

i cant see that

Step-by-step explanation:

3 0
3 years ago
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