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Ipatiy [6.2K]
4 years ago
6

The ratio of cars to trucks is 9 to 4. If 4 there are 52 trucks, what is the number of cars? Explain how you got your answer

Mathematics
2 answers:
CaHeK987 [17]4 years ago
7 0

Answer:

Step-by-step explanation:

9 to 4

117 cars

4*13=52

9*13=117

Phantasy [73]4 years ago
3 0

Answer:

117 cars.

Step-by-step explanation:

Hi Yirod!

To begin, we need to find out what 52 ÷ 4 is. That's because there are 4 trucks in the ratio, but a total of 52 trucks.

52 ÷ 4 = 13

So we're multiplying everything by 13.

9 × 13 = 117

So there are $\boxed{117}$ cars.

<u>Check:</u>

Since we have 52:117, it should simplify to 9:4

52:117 (divide both by 13)

9 : 4. Thus, we are correct!

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On a website, listeners rate music from 1 star to 5 stars. One song was rated 1 star by 3.5% of the listeners. There were 49 lis
defon

Answer:

1400

Step-by-step explanation:

3.5% of listeners rated the song as 1 star

49 listeners rated the song as 1 star

49 listeners = 3.5% of listeners

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3 years ago
Someone who explain me please
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First you need to isolate the variable so for #1 I would add 2t on both sides and add 3 on both sides. That makes the inequality -4t<-16. Then divide both sides by -4 to get t<4. This means that t is less than 4 so you need to draw an open circle on four on the number line and draw an arrow pointing to everything less than 4. ( If the inequality is equal to and less than/ greater than a # shade in the circle.)
5 0
3 years ago
If p is the incenter of triangle jkl, find each measure
Hunter-Best [27]

Answer:

PO = 7

PM = 7

MJ = 11

∠PJO = 32°

∠KJL = 64°

PL ≈ 18.385

OL = 17

∠PLO = 22°

∠NLO = 44°

∠JKL = 72°

∠MKP = 36°

∠NKP = 36°

∠PKN = 36°

KN = 10

PL ≈ 13.04

PK ≈ 12.21

JL = 28

JK = 21

LK = 27

Step-by-step explanation:

The given parameters are;

The point representing the incenter of the triangle = P

Therefore PO = PM = PN = 7

tan(32°) = PM/JM = 7/JM

∴JM = 7/(tan(32°)) ≈ 11.2

∠PJO = tan⁻¹(7/11)≈ 32.47°

∠PJO = ∠PJM = 32° similar triangles

∠KJL = ∠KJP + ∠PJO = 32 + 32 = 64°

∠KJL ≈ 64°

PL = √(7² + 17²) ≈ 18.385

OL = NL = 17 similar triangles

∠PLO = sin⁻¹(7/18.385) ≈ 22.380°

∠PLO = ∠PLN = 22°

∠NLO = ∠PNL + ∠OLP ≈ 22° + 22° ≈ 44°

∠NLO ≈ 44.380°

∠JKL = 180 - (∠KJL + ∠NLO)

∠JKL = 180° - (64° + 44°) ≈ 72°

∠JKL  ≈ 72°

∠MKP = ∠NKP = 72°/2 = 36°

∠MKP = 36°

∠NKP = 36°

∠PKN = ∠JKL - ∠MKP = 72° - 36° ≈ 36°

∠PKN  ≈ 36°

KN = KM = 10

MJ = OJ = 11

PL = √(7² + 11²) ≈ 13.04

PK = √(7² + 10²) ≈ 12.21

JL = JO + OL = 11 + 17 = 28

JK = JM + MK = 11 + 10 = 21

LK = LN + NK = 17 + 10 = 27

6 0
3 years ago
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