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Nookie1986 [14]
2 years ago
6

11. What values of a, b, and c make this equation true?

Mathematics
1 answer:
borishaifa [10]2 years ago
4 0

9514 1404 393

Answer:

  A,  a = 4, b = -3, c = 3

Step-by-step explanation:

Expanding the left side gives ...

  2x^2 -x -10 +ax^2 +bx +c

  = (2 +a)x^2 +(b -1)x +(c -10)

Equating coefficients with terms on the right side gives ...

  x^2: (2 +a) = 6   ⇒   a = 4 . . . . . . eliminates choice C

  x: (b -1) = -4   ⇒   b = -3 . . . . . . . . eliminates choices B, D

  constant: c -10 = -7   ⇒   c = 3 . . . confirms choice A

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Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.
Pepsi [2]

Answer:

x=20

y=10\,\sqrt{3}

Step-by-step explanation:

In the triangle we have the following trigonometric equations:

tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}

and also:

cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20

8 0
3 years ago
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