11. What values of a, b, and c make this equation true?
1 answer:
9514 1404 393
Answer:
A, a = 4, b = -3, c = 3
Step-by-step explanation:
Expanding the left side gives ...
2x^2 -x -10 +ax^2 +bx +c
= (2 +a)x^2 +(b -1)x +(c -10)
Equating coefficients with terms on the right side gives ...
x^2: (2 +a) = 6 ⇒ a = 4 . . . . . . eliminates choice C
x: (b -1) = -4 ⇒ b = -3 . . . . . . . . eliminates choices B, D
constant: c -10 = -7 ⇒ c = 3 . . . confirms choice A
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Answer:
x=24
Step-by-step explanation:
The Quotient(dividing) of a number(x) and 6 minus(-) 3 IS(=) 1.
Which turns into:
- 3 = 1
We want to get x by itself so we divide the entire equation by 6.
6 ( - 3 = 1 )
x - 18 = 6
We want to move the plain numbers to one side so x can be by itself. So we add 18 to both sides.
x = 24