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Nezavi [6.7K]
3 years ago
9

How can u get from 2 to 21

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

Add 19

Step-by-step explanation:

NemiM [27]3 years ago
3 0

Answer:

Times

Step-by-step explanation:

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What is the area of a circle with the diameter of 10cm ?
8_murik_8 [283]

Answer:

A≈78.54cm² Diamter= 10

Step-by-step explanation:

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7 0
3 years ago
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xeze [42]

Answer:

54

Step-by-step explanation:

5 0
3 years ago
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Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?
Veronika [31]

Answer:

A) 2k+4

Step-by-step explanation:

To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.

To start, we will cross multiply. If we have a/b=c/d, then ad=bc

We can perform the same calculation here,

6/x=3/(k+2)

6(k+2)=3x

Divide both sides by 3

2(k+2)=x

x=2k+4

7 0
4 years ago
Perpendicular to the line y=1/2x-8; passes through (7,-6). Write the slope-intercept form of the equation.
Airida [17]

<u>ANSWER: </u>

The slope intercept form of the required line is y = -2x + 20.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{1}{2} x-8$

And, Perpendicular line to the given line  passes through (7,-6).  

We need to find the slope intercept form of perpendicular line of given line.  

We already have the point (7, -6) but we need to find the slope.

Now, we know that, product of slopes of two perpendicular lines equals to -1.

Slope of given line is \frac{1}{2}, by comparing with the general form of slope intercept form.

\frac{1}{2} \times slope of required line = -1

Slope of perpendicular line = -2

Now, line equation of perpendicular line in point slope form is

$y-y_{1}=m\left(x-x_{1}\right)$

y – (-6) = -2(x – 7)

y + 6 = -2x + 14

y = -2x + 20

the above equation is in the form of slope intercept form of a line equation  

where slope m = -2 and intercept c = 20

hence, the slope intercept form of the required line is y = -2x + 20.

6 0
3 years ago
Let u = (1,2), v = (−3,4), and w = (5,0)
sergij07 [2.7K]

Answer:

w-2u-v

Step-by-step explanation:

Given are three vectors u, v and w.

In R^2 we treat first element as x coordinate and 2nd element as y coordinate.

Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.

b) w=au+bv

We have to find the values of a and b

(5,0) = a(1,2)+b(-3,4)]

Equate the corresponding terms

5=a-3b\\0=2a+4b

Divide II equation by 2 to get

0=a+2b

Eliminate a

-5 = 5b: b=-1

a=-2

Hence

w = 2u-v

7 0
3 years ago
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