Answer:
length=53 in
width= 23 in
Step-by-step explanation:
First, we know that each corner has now a square of 6 in long, so the heigth of the box will be of this size (as you can see in the picture attached). Then, the length and the width of the box would be the same as the piece, but with 12 in less. Therefore the equations to solve the problem are:
We factorize the 6 and we get:
Finally we solve for x, and we get the initial dimensions of the piece of metal:
Answer:
8,11,14,17,20,23,26
Step-by-step explanation:
Q = 3n+ 5
an=3n+5
a1=3(1)+5=8
a2=3(2)+5=11
a(3)=3(3)+5=14
a4=3(4)+5=17
a5=3(5)+5=20
a6=23
a7=26
Answer:
Step-by-step explanation:
The relevant rule of exponents is ...
(a^b·c^d)^e = a^(be)·c^(de)
Then ...
(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)
= m^(35/12)·n^(-28/15)
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Since you want positive rational exponents, you can write this as ...
= m^(35/12)/n^(28/15)
1/8 is your answer
-Hope this helps
Use PEMDAS, the answer that I got is 19.
