X < - 1)x 1 X *+8 That’s it
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For this case, the first thing we must do is define variables.
We have then:
x: number of checks.
y: total cost.
We now write the linear function that represents the problem.
We have then:
Then, Jerome issues 10 checks in a month.
Therefore, we evaluate the function for x = 10.
We have then:
Answer:
a monthly checking account will cost him about:
y = 12.5 $
We have then:
x: number of checks.
y: total cost.
We now write the linear function that represents the problem.
We have then:
Then, Jerome issues 10 checks in a month.
Therefore, we evaluate the function for x = 10.
We have then:
Answer:
a monthly checking account will cost him about:
y = 12.5 $
See the picture for all detail, I have done it by hand.
Few important steps;
-Take the first derivative
-Put it equal to zero
-you get the x value which is equal to 11
-Now for the check that x=11 is the least value or not, take the second derivative
-As, the 2nd derivative is positive so it is the least value
As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value
Few important steps;
-Take the first derivative
-Put it equal to zero
-you get the x value which is equal to 11
-Now for the check that x=11 is the least value or not, take the second derivative
-As, the 2nd derivative is positive so it is the least value
As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value