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Gennadij [26K]
3 years ago
9

Suppose we take a random sample of 41 state college students. Then we measure the length of their right foot in centimeters. We

compute a 95% confidence interval for the mean foot length for students at this college. We get (21.71, 25.09). Suppose that we now compute a 90% confidence interval. As confidence level decreases, the interval width .
Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

As confidence level decreases, the interval width decreases too.

Step-by-step explanation:

The confidence interval is an interval in which is probable that the true value of an unknown variable is contained. The confidence level is the probability that this true value is within the limits of the interval.

The degree of confidence or confidence level is defined and affects the width of the confidence interval.

If the true value of the mean foot length is within 21.71 and 25.09 with a 95% confidence level, if we decrease the confidence level to 90%, we expect to have an interval with smaller width.

When we increase the confidence level, we expect to be more sure about the true value being contained in the interval. As we do not count with new information, the only way to be more sure is to have a wider interval.

If the confidence level decreases, we can have a narrower confidence interval as we are not so severe with the probability of containing the true level.

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Ipatiy [6.2K]

Answer:

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
2 years ago
Which of the following choices is the simple formula for the nth term of the following arithmetic sequence?
VladimirAG [237]
First, we start off with the nth term formula for an arithmetic sequence, which is 
a_{n} =a_{1}+(n-1)d

plug in the sequence numbers where they belong

a_{n}=5+(n-1)*(-4)

a_{n}=5+(-4n+4)
a_{n}=5-4n+4
a_{n}=-4n+9

And this is the final answer
-4n+9
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A group of 15 friends take a trip to a water park. The total price of the trip is $599.85 before any discounts. The total price
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Answer:10

Step-by-step explanation:

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3 years ago
The summit of a mountain pass is 8,050 ft above sea level. the valley below is 12 and 1/2 ft below sea level. what is the vertic
Veseljchak [2.6K]

Answer:

Vertical distance between the valley and the summit = 8062.5 ft

Step-by-step explanation:

Distances above the sea level are denoted by positive notations and below the sea level by negative notation.

Summit of a mountain pass = 8050 (above the sea level)

Valley below the sea level = 12 and half ft = (-12.5) ft

Distance between the summit and the valley = 8050 - (-12.5)

                                                                           = 8050 + 12.5

                                                                           = 8062.5 ft

Therefore, Vertical distance = 8062.5 ft will be the answer.

5 0
3 years ago
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tino4ka555 [31]

Answer:

x = 24

Step-by-step explanation:

10:8

10(3) = x(3)

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7 0
3 years ago
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