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Gennadij [26K]
3 years ago
9

Suppose we take a random sample of 41 state college students. Then we measure the length of their right foot in centimeters. We

compute a 95% confidence interval for the mean foot length for students at this college. We get (21.71, 25.09). Suppose that we now compute a 90% confidence interval. As confidence level decreases, the interval width .
Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

As confidence level decreases, the interval width decreases too.

Step-by-step explanation:

The confidence interval is an interval in which is probable that the true value of an unknown variable is contained. The confidence level is the probability that this true value is within the limits of the interval.

The degree of confidence or confidence level is defined and affects the width of the confidence interval.

If the true value of the mean foot length is within 21.71 and 25.09 with a 95% confidence level, if we decrease the confidence level to 90%, we expect to have an interval with smaller width.

When we increase the confidence level, we expect to be more sure about the true value being contained in the interval. As we do not count with new information, the only way to be more sure is to have a wider interval.

If the confidence level decreases, we can have a narrower confidence interval as we are not so severe with the probability of containing the true level.

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Waht is the value of ((2/3)^0)^-3​
mestny [16]

Answer:

\left(\left(\frac{2}{3}\right)^0\right)^{-3}=1

Step-by-step explanation:

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(\left(\frac{2}{3}\right)^0\right)^{-3}=\left(\frac{2}{3}\right)^{0\cdot \left(-3\right)}\\=\left(\frac{2}{3}\right)^0\\=1

<3

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6 0
3 years ago
A stamp has the Length of 1/2 cm and a width of 1 1/2 is the area of the stamps
avanturin [10]

Answer:

Area =  \frac{3}{4} cm^2

Step-by-step explanation:

Given

Length =\frac{1}{2}\ cm

Width = 1\frac{1}{2}\ cm

Required

Determine the Area

Area is calculated as follows

Area = Length * Width

Substitute values for Length and Width

Area = \frac{1}{2} * 1\frac{1}{2}

Convert mixed fraction

Area = \frac{1}{2} * \frac{3}{2}

Area =  \frac{3}{4}

Hence, the area is

Area =  \frac{3}{4} cm^2

3 0
3 years ago
HELP PLEASE 50 points !!! Given a polynomial function describe the effects on the Y intercept, region where the graph is incre
Gwar [14]

Even function:

A function is said to be even if its graph is symmetric with respect to the , that is:

Odd function:

A function is said to be odd if its graph is symmetric with respect to the origin, that is:

So let's analyze each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When  becomes  

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

We know that the graph  intersects the y-axis when , therefore:

So:

So the y-intercept of  is one unit less than the y-intercept of

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function  increases and decreases in the same intervals of

1.3 The end behavior when the following changes are made.

The function is shifted one unit downward, so each point of  has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:

FOR ODD FUNCTIONS:

2. When  becomes  

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.

An example is shown in Figure 1. The graph in blue is the function:

and the function in red is:

So you can see that:

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of

In Figure 1 you can see that both functions increase at:

and decrease at:

2.3 The end behavior when the following changes are made.

It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When  becomes  

3.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

As we know, the graph  intersects the y-axis when , therefore:

And:

So the new y-intercept is the negative of the previous intercept shifted one unit upward.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

3.3 The end behavior when the following changes are made.

Each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:

FOR ODD FUNCTIONS:

4. When  becomes  

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward.

6 0
3 years ago
Which is greater 76% or 7/9 or are they bothe equal
Ne4ueva [31]
7/9 is 77.7, as far as I know.
6 0
3 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

N ⊂ Z ⊂ Q ⊂ R .

4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

4 0
3 years ago
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