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Dmitry [639]
3 years ago
5

Derive the equation of the parabola with a focus at (-5, 5) and a directrix of y = -1.

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

answer is D

Step-by-step explanation:

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Write the equation of a direct variation that passes through the point (- 11, 13)
jek_recluse [69]

Answer:

b. y = - 1.18X

Step-by-step explanation:

y = - 1.18X

y = - 1.18 x -11 = 12.98     (≈ 13)

3 0
3 years ago
A rectangular plot is 65m long and 32m wide. Find the area of the plot and the cost of it if 1m2 costs Rs2590.
zhannawk [14.2K]

Answer:

length =65m

breadth =32m

area=l×b

=65×32

=2080m^2

now,

total cost=Rate×Area

=2590×2080

=Rs 5387200

8 0
3 years ago
You run 4 miles in 1 hour. At this rate, how long will it take you to run 22 miles?
Evgen [1.6K]
4 miles  in  1 hour.

1 mile will be covered in  (1/4) hour.

22 miles will then be covered in:        22 * 1/4 = 11/2 = 5.5

22 miles will be covered in 5.5 hours.
8 0
4 years ago
The sum of 25/4 and three times a number is equal to 3/4 subtracted from four times the number. find the number
stich3 [128]
For an instance, n represents the number
\frac{25}{4}+n=4n- \frac{3}{4}
n-4n=-\frac{3}{4}-\frac{25}{4}
-3n=-\frac{28}{4}
n=-\frac{28}{4} \times -\frac{1}{3}
n= \frac{28}{12}
n= \frac{7}{3}

The number is 7/3
5 0
3 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
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