This question is incomplete because it was not written properly
Complete Question
A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)
a) 20%
b) 40%
c) 60%
d) 75%
Answer:
d) 75%
Step-by-step explanation:
We would be solving this question using conditional probability.
Let us represent the percentage of those who passed the first quiz as A = 80%
and
Those who passed the first quiz as B = unknown
Those who passed the first and second quiz as A and B = 60%
The formula for conditional probability is given as
P(B|A) = P(A and B) / P(A)
Where,
P(B|A) = the percent of those who passed the first one passed the second
Hence,
P(B|A) = 60/80
= 0.75
In percent form, 0.75 × 100 = 75%
Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.
Answer:
D. It would be less steep
Step-by-step explanation:
The first graph moves at a rate of 5/1 which is a greater fraction than 3/4
- The second graph is shallow due to the close points in x and y that are able to be conducted
- The first Graph rapidly increases at a way higher rate making it VERY steep
- While both are linear the second strays away in terms of plot lines
Answer:
3
Step-by-step explanation:
P is the in-center
⇒PA=PE=PD because they are in-radius of the in-circle
We know that, tangent segments drawn from a point outside the circle are always equal in length
⇒DK=EK=7.2
In right triangle PKE,
using Pythagoras' Theorem : 
⇒
⇒
⇒
⇒
Therefore, 
Answer:
slope = -3/4
Step-by-step explanation:
Slope:
−
3/4
y-intercept:
13
/4
Any line can be graphed using two points. Select two values, and plug them into the equation to find the corresponding values.
x | y
0 | 13
/4
1 | 5/
2
Hope this helps @(^_^)@
