As the volume of the container increases, the gas pressure decreases. They are directly proportional. This is supported by Boyle's Law.
3.75 litres is the volume of the balloon indoors at a temperature of 25°C.
Explanation:
Data given:
initial temperature of the gas in balloon = -35°C or 238.15 K
initial volume = 3 litres
final temperature = 25 °C or 298.15 K
final volume =?
pressure remains constant
From the data given when pressure is constant Charles' law is applied.
= 
Rearranging the equation to know the final volume of the gas in balloon
V2 = 
V2 = 
V2 = 3.75 Litres
when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.
Answer:
- a) 2N₂O(g) → 2N₂(g) + O₂(g)
Explanation:
Arrange the equations in the proper way for better understanding.
T<em>he reaction between nitrogen and oxygen is given below:</em>
<em />
- <em>2N₂(g) + O₂(g) → 2N₂O(g)</em>
<em />
<em>We therefore know that which of the following reactions can also occur?</em>
<em />
- <em>a) 2N₂O(g) → 2N₂(g) + O₂(g)</em>
- <em>b) N₂(g) + 2O₂(g) → 2NO₂(g)</em>
- <em>c) 2NO₂(g) → N₂(g) + 2O₂(g)</em>
- <em>d) None of the Above</em>
<h2>Solution</h2>
Notice that the first equation, a) 2N₂O(g) → 2N₂(g) + O₂(g), is the reverse of the original equation, 2N₂(g) + O₂(g) → 2N₂O(g).
The reactions in gaseous phase are reversible reactions that can be driven to one or other direction by modifying the conditions of temperature or pressure.
Thus, the equilibrium equation would be:
Which shows that both the forward and the reverse reactions occur.
Whether one or the other are favored would depend on the temperature and pressure: high temperatures would favor the reaction that consumes more heat (the endothermic reaction) and high pressures would favor the reaction that consumes more moles.
Thus, by knowing that one of the reactions can occur you can conclude that the reverse reaction can also occur.
Answer:
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Explanation:
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