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andre [41]
3 years ago
10

Pleas help please answer it correctly please if it’s correct I will mark you brainliest

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

The probability is 2/3

Step-by-step explanation:

<u>Step 1:  Find the probability</u>

hip-hop / other

8 / 12

<u>Step 2:  Simplify</u>

(8/4) / (12/4)

2 / 3

Answer:  The probability is 2/3

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What set of numbers are shaded on the
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Answer:

D - 20, 40, 60, 80, 100 are all multiples of 20

Step-by-step explanation:

Factors of 10 - 10, 5, 2, 1

Multiples of 10 - D and 10, 30, 50, 70, 90

Factors of 20 - 20, 10, 5, 4, 2, 1

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3 years ago
a farmer has 100m for fence avaibiable, with which he intends to build a pen for his sheep. he intends to create a rectangular p
Reika [66]

The perimeter of the area of the pen the farmer intends to build for his

ship includes the length of the permanent stone wall.

Response:

i) The length and width of the rectangular pen are; <em>x</em>, and \dfrac{100 - x}{2}, therefore;

  • The area is; A = \dfrac{1}{2} \cdot x \cdot (100 - x)

ii) \hspace{0.5 cm}\dfrac{dA}{dx}  = 50 - x

\dfrac{d^2A}{dx^2} =  -1

iii) The value of <em>x</em> that makes the area as large as possible is x = 50

<h3>How is the function for the area and the maximum area obtained?</h3>

Given:

The length of fencing the farmer has = 100 m

Part of the area of the pen is a permanent stone wall.

Let <em>x</em> represent the length of the stone wall, we have;

2 × Width = 100 m - x

Therefore;

Width, <em>w</em>, of the rectangular pen, w = \mathbf{\dfrac{100 - x}{2}}

Area of a rectangle = Length × Width

Area of the rectangular pen, is therefore;

  • A = x \times \dfrac{100 - x}{2} = \underline{\dfrac{1}{2} \cdot x \cdot (100 - x)}

ii) \hspace{0.5 cm} \mathbf{\dfrac{dA}{dx}}, and \mathbf{\dfrac{d^2A}{dx^2} } are found as follows;

\dfrac{dA}{dx} = \mathbf{\dfrac{d}{dx} \left(  \dfrac{1}{2} \cdot x \cdot (100 - x) \right)} = \underline{50 - x}

\dfrac{d^2A}{dx^2} = \mathbf{ \dfrac{d}{dx} \left( 50 - x\right)} = \underline{-1}

iii) The value of <em>x</em> that makes the area as large as possible is given as follows;

Given that the second derivative, \dfrac{d^2A}{dx^2} =-1, is negative, we have;

At the maximum area, \dfrac{dA}{dx} = \mathbf{0}, which gives;

\dfrac{dA}{dx} = 50 - x = 0

x = 50

  • The value of x that makes the area as large as possible is <em>x</em>  =<u> 50</u>

Learn more about the maximum value of a function here:

brainly.com/question/19021959

7 0
2 years ago
Please helpme how is this: b+8= -4
mr_godi [17]
-12. Subtract 8 from both sides.
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Given the following equation where A = Area of a rectangle and w = width of the rectangle, what value of 'w' would maximize the
Papessa [141]

Answer:

the second option : w should be 25 units

Step-by-step explanation:

the area of the rectangle is length×width = L×W

the perimeter of a rectangle = 2L + 2W

now, we know that the perimeter is 100 units.

and we have to find the best length of W, that will then define L (to keep the 100 units of perimeter) and maximizes the area of the rectangle.

in other words, what is the maximum area of a rectangle with perimeter of 100 (and what are the corresponding side lengths)?

now, w = 625 is impossible. that side alone would be bigger than the whole perimeter.

W = 0 would render the whole rectangle to a flat line with L = 50 because of

100 = 2L + 2W = 2L + 0 = 2L

L = 50

and A = L×W = 50×0 = 0

an area of 0 is for sure not the largest possible area.

w = 50 would cause L = 0

100 = 2L + 2W = 2L + 2×50 = 2L + 100

0 = 2L

L = 0

and with L = 0 the same thing happens as with W = 0 : a flat line with 0 area.

so, the only remaining useful answer is W = 25

100 = 2L + 2W = 2L + 2×25 = 2L + 50

50 = 2L

L = 25

A = L×W = 25×25 = 625 units²

and indeed, the maximum area for a given perimeter is achieved by arranging the sides to create a square.

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