<h3><em>Answers:</em></h3><h2 /><h2>1/4 + 2/3 =11/12</h2><h2 /><h2>2/5-1/10= 3/10</h2><h2 /><h2>1/6+1/4=5/12</h2><h2 /><h2>5/8-1/4=3/8</h2><h2 /><h2>7/8-1/2=3/8</h2><h2 /><h2>3/10+4/5=11/10 or 1 1/10</h2><h2 /><h2>5/6-2/5=3/5</h2><h2 /><h2>5/12-1/4=1/6</h2><h2 /><h2>7/16+1/8=9/16</h2><h2 /><h2>11/16+5/8=21/16 or 1 5/16</h2><h2 /><h2>2/7+1/2=11/14</h2><h2 /><h2>4/5+3/4=31/20 or 1 11/20</h2>
Answer:
sin B sin C. When this equation is combined with the previous equation, we obtain the Law of. Sines. ... ас. B. FIGURE 4.5 Solving an. ASA triangle. Keep in mind that we must be given one of the three ratios to apply the ...
Answer:
L.C.M of 15 and 30 is 30.
Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
