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Burka [1]
3 years ago
9

Miles is planning to spend 2/3 as many hrs bicycling this week as he did last week. Is Miles going to spend more hrs or fewer hr

s bicycling this week than last week? ( I'm working on comparing fraction factors and products- multiplying fractions)
Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0
He would be spending less time because  2/3 is not a full number. Let's make an equation out of the: 2/3(m). Note: 3(2) means 3 times 2 and the m is the amount of miles biked last week. We could insert the number 3 to our equation. 2/3(3). Now if you do it the proper way, it is 2/3(3/1) and if you do the math it is 6/3 aka 2. And 2 is less than 3. So it is less time spent
Elden [556K]3 years ago
5 0
Miles is going to spend less hours this week
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Express 81 as the sum of first nine consecutive odd numbers
matrenka [14]

Answer:

see explanation

Step-by-step explanation:

The sum of the first 9 consecutive odd numbers is

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 81

3 0
3 years ago
A river drops 12 ft vertically over a horizontal distance of 1500 ft.
elixir [45]

Answer:

Slope = rise / run

= -12 / 1500 (It's -12 and not 12 because a drop means it's decreasing)

= -0.008

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3 years ago
Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h​) <br>​
mel-nik [20]

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

7 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

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8 0
2 years ago
A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A
Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias  = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}

If you divide both you can get the growth rate:

\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000

7 0
3 years ago
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