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goblinko [34]
3 years ago
5

Convert 10 1/2 to fractional notation

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0
10 1/2 =
10/1 + 1/2=
2/2 (10/1) + 1/2=
20/2 + 1/2=
21/2 

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Write <br> 6<br> :<br> 9<br> :: <br> 2<br> :<br> 3<br> as a fraction proportion.
Firdavs [7]
6/9 (2/3) and 2/3. Hope this helps you.
3 0
2 years ago
Please help me answer this.
TiliK225 [7]
8x2+6x-2

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2 years ago
3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h
lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's  flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where  u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t  - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards  with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis  gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0
3 years ago
Read 2 more answers
-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)
Korolek [52]
-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}

=========================================================

8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}

=========================================================

10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}
6 0
3 years ago
Read 2 more answers
Choose the correct word that completes each statement about inscribing a square in a circle.
Anna11 [10]

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB²  ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius


7 0
2 years ago
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