Step-by-step explanation:
In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)
2.5(6-x) = 0
Open the bracket,
(2.5×6)-2.5x= 0
Collect like terms.
2.5x= 2.5×6
Divide both sides by the coefficient of x (2.5)
x = 6
So,
x= 6 is true.
.
Substituting 6 for x in the equation,
2.5(6-6)= 0
2.5•0 = 0
0= 0
Which is also true.
F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4
Hey there!!
- The area of a circle = πr²
The area is given as 196π
Hence,
196π = πr²
... r²= 196
... r = √196
... r = 14
<em>Hence, the radius is 14 cm. </em>
<em>Hope it helps!</em>
