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Nadusha1986 [10]
3 years ago
15

Rewrite the function y = x^2 - 6x + 14 in vertex form, y = (x - h)^2 + k.

Mathematics
2 answers:
velikii [3]3 years ago
8 0

Answer: y = (x - 3)² + 5

<u>Step-by-step explanation:</u>

  y   = x² - 6x + 14

<u>   -14 </u>   <u>             -14 </u>

y - 14 = x² - 6x

y - 14 + <u>  9  </u> = x² - 6x + <u>  9  </u>

             ↑            ↓       ↑

                         \frac{-6}{2} = (-3)²

y - 5 = (x - 3)²

<u>   +5 </u>    <u>          +5 </u>

y      = (x - 3)² + 5

Mila [183]3 years ago
3 0

the equation of a parabola in

vertex form

is.


¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

a

(

x

−

h

)

2

+

k

2

2

∣

∣

∣

−−−−−−−−−−−−−−−−−−−−−


where

(

h

,

k

)

are the coordinates of the vertex and a


is a multiplier


to obtain this form

complete the square


y

=

x

2

+

2

(

4

)

x

+

16

−

16

+

14


⇒

y

=

(

x

+

4

)

2

−

2

←

in vertex form


⇒

vertex

=

(

−

4

,

−

2

)


to obtain the intercepts


∙

let x = 0, in the equation for y-intercept


∙

let y = 0, in the equation for x-intercept


x

=

0

⇒

y

=

0

+

0

+

14

=

14

←

y-intercept


y

=

0

⇒

(

x

+

4

)

2

−

2

=

0

←

add 2 to both sides


⇒

(

x

+

4

)

2

=

2


take the square root of both sides


√

(

x

+

4

)

2

=

±

√

2

←

note plus or minus


⇒

x

+

4

=

±

√

2

←

subtract 4 from both sides


⇒

x

=

−

4

±

√

2

←

exact values

graph{(y-x^2-8x-14)((x+4)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}

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