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3 years ago

Anna has a square shaped cardboard of surface (x2 + 12x + 36) cm2. Find the side of the cardboard

Mathematics

2 answers:

OverLord2011 [107]3 years ago

7 0

Answer:

Step-by-step explanation:

A square surface is determined by the product of its sides

s = L ^ 2

Thus, the surface of the cardboard of side C, will be

x ^ 2 + 12x + 36 = C ^ 2

Factoring

(x + 6) (x + 6) = C ^ 2

THE SIDE IS (x + 6)

slega [8]3 years ago

3 0

Answer:

$\boxed{(x+6)}$

Step-by-step explanation:

The surface of a square is $\sf side^2$ .

$s^2 =x^2 +12x+36$

Take the square root on both sides.

$s=\± \sqrt{x^2+12x+36}$

$s=\± (x+6)$

The side of the cardboard cannot be a negative value.

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Illusion [34]

Answer:

Step-by-step explanation:

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3 years ago

An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle

omeli [17]

Answer:

$\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

$\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}$

The middle point of the base is placed at point

$\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i$

The length of the height is the distance between the points 5+9i and 7+3i

$\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}$

So, the area of the triangle is

$A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}$

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2 years ago