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Alona [7]
3 years ago
8

Is the number below a perfect square how do you know 2 x 2 x 3 x 5 x 5​

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

nope

nope

nopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenopenope

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Y = 4(x - 2)(x + 6)<br> what is this factored out
lutik1710 [3]
Y=4x^2+16x-48

Start with factoring (x-2)(x+6) using distribution
Then multiply it by 4
4 0
3 years ago
Point K is on line segment JL. Given KL = 7 and JL = 11, determine the length JK.
Setler [38]

Answer:

4

Step-by-step explanation:

11 - 7 = 4

6 0
3 years ago
To create an entry code you must choose the first three letters and three single digit numbers how many different entry code can
Dmitry_Shevchenko [17]

Answer:

9

Step-by-step explanation:

3*3=9

ABC and 123

A1 B1 C1 A2 B2 C2 A3 B3 C3

7 0
3 years ago
Can someone please help? This is difficult.
galina1969 [7]

They intersect at a point called the centroid. See the attached sketch.

4 0
3 years ago
WILL GIVE A BRAINLESTTTT<br><br> What is the solution of 3x+8/x-4 &gt;= 0
Blababa [14]
Solution: (-Infinite, -8/3] U (4, Infinite)

Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0

Or (U)

Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0

In this case a=3x+8 and b=x-4, then:

Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)

Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]

Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)
7 0
4 years ago
Read 2 more answers
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