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3 years ago

How do you find the area of a parallelogram

Mathematics

2 answers:

dmitriy555 [2]3 years ago

6 0

Answer:A=Bh

Step-by-step explanation:

follow this and you'll get the answer!

If you don't understand what this means:

The answer equals the base times the height

guajiro [1.7K]3 years ago

4 0

Answer:

Opposite sides are equal in length and opposite angles are equal in measure. To find the area of a parallelogram, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

Step-by-step explanation:

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The table shows values for the equations of a system:

zheka24 [161]

Answer:

Use a graphing calculator to check your answer. ... g(x) = 2/4x+3/+5. 94) = 2x. Page 2. 8 . Solve the system without a calculator. ... 9. Solve the

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3 years ago

Find equations of the line that is parallel to the z-axis and passes through the midpoint between the two points (0, −3, 7) and

tia_tia [17]

Answer:

$\vec{r}(t)=\left$

In parametric form:

$x=-1, y=\displaystyle\frac{1}{2}, z=4+t$

Step-by-step explanation:

We first find the mid point:

$\displaystyle\left(\frac{0+(-2)}{2},\frac{-3+4}{2},\frac{7+1}{2}\right)=\left(-1,\frac{1}{2},4\right)$

Then, a vector parallel to the z-axis is:

$\vec{v}=\left< 0,0,1 \right>$

Then remember the equation of a line passing through point $(x_o,y_o,z_o)$ and parallel to the vector $\vec{v}=\left$ is:

$\vec{r}(t)=\left+t\left$

So, in this problem we get:

$\vec{r}(t)=\left+t\left$

After combining the two vectors:

$\vec{r}(t)=\left$

In parametric form:

$x=-1, y=\displaystyle\frac{1}{2}, z=4+t$

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3 years ago

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Korolek [52]

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3 years ago

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Dafna11 [192]

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3 years ago

Check each equation whose graph is the line that

yanalaym [24]

Answer:

Points P ( 4 , - 7 ) and Q ( 1 , 5 ) belong to the equations:

1 ; 4 ; and 5

Step-by-step explanation:

Equations 1 ; 4 and 5 are the same equation

Equation 1 y = - 4*x + 9

Equation 4

y + 7 = - 4 * ( x - 4 ) ⇒ y + 7 = - 4*x + 16 ⇒ y = - 4*x - 7 + 16

y = -4*x + 9

Equation 5

4*x + y = 9 ⇒ y = - 4*x + 9

Now for the equation y = - 4*x + 9

P ( 4 , -7)

For x = 4 y = - 4*(4) + 9 ⇒ y = - 16 + 9 ⇒ y = - 7

Then point P is in the line y = - 4*x + 9

Point Q (1 , 5 )

For x = 1 y = - 4 * ( 1) + 9 ⇒ y = - 4 + 9 ⇒ y = 5

Point Q is in the line y = - 4*x + 9

Equation 2

y = - 4*x - 23

Point P ( 4 , - 7 )

For x = 4 y = 16 - 23 y = - 7

Point P is in the line

Point Q

For x = 1 y = - 4 *(1) - 23 ⇒ y = - 27

Then poin Q is not in the line

Equation 3

y - 1 = - 4 * ( x - 4 )

y - 1 = -4*x + 16 ⇒ y = - 4*x + 17

Point P ( 4 , - 7 )

For x = 4

y = - 16 + 17 ⇒ y = 1

Point P is not in the line

And Point Q ( 1 , 5 )

For x = 1

y = - 4* ( 1 ) + 17 ⇒ y = 13 Q is not in the line

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3 years ago