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love history [14]
3 years ago
14

Through: (2,5), perp. to y =- 2/3x +3

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Find the equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3

<h3><u>Answer:</u></h3>

The equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3 in slope intercept form is y = \frac{3}{2}x + 2

<h3><u>Solution:</u></h3>

Given that line passes through (2, 5) and perpendicular to line having equation y = \frac{-2}{3}x + 3

Let us first find slope of original line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form y = mx + c and given equation of line y = \frac{-2}{3}x + 3 we get

m = \frac{-2}{3}

Thus slope of given line is m = \frac{-2}{3}

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

Slope of given line x slope of line perpendicular to it = -1

\begin{array}{l}{\frac{-2}{3} \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{3}{2}}\end{array}

Let us find equation of line with slope m = \frac{3}{2} and passes through (2, 5)

Substitute m = \frac{3}{2} and (x, y) = (2, 5)

5 = \frac{3}{2} \times 2 + c\\\\5 = 3 + c\\\\c = 2

<em><u>Thus the required equation of line is:</u></em>

Substitute m = \frac{3}{2} and c = 2 in eqn 1

y = \frac{3}{2}x + 2

Thus the equation of line perpendicular to given line is found out

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