Answer: P = $ 12000
r = 14%
t = 1 (for first year)
I = (P X r X t)/100
∴ I = (12000 X 14 X 1)/100
= 120 X 14
= $ 1680 <---------- (Interest on loan at the end of first year)
∴ Total amount owing at the end of first year = (P + I)
= (12000 + 1680)
= $ 13680
Repayment = $ 7800
Amount still outstanding (at the start of second year) = 13680 - 7800
= $ 5880
Interest on the outstanding amount at the end of second year,
P (new) = $ 5880
r (same) = 14%
t = 1 (for the current second year)
∴ I = (P X r X t)/100
= (5880 X 14 X 1)/100
= 82320 / 100
= $ 823.2 <-------------------------- (Interest on outstanding amount at the end of second year)
Y = -2x + 1
y = -2x + 2
y = -2x + 3
these are all parallel lines because they have the same slopes (-2) but different y intercepts.
y = 3x + 4
y = -1/3x + 3
these are perpendicular lines because they have negative reciprocal slopes.
slope of a line parallel to the x axis : If it is parallel to the x axis, it is a horizontal line and has a slope of 0.
slope of a line perpendicular to the x axis : if it is perpendicular to the x axis, it is a vertical line with a slope that is undefined.
slope of line parallel to the y axis : vertical line, undefined slope
slope of a line perpendicular to the y axis : horizontal line, slope of 0
It’s 25.5 because since 25 off of 100 equals 75, you times the 34 by .75
(3600)(7.5x-10x-10)
Calculate the difference
3600x(-2.5x-10)
Multiply the values
(3600x -2.5x-3600x10)
write the value as a fraction
and so your answer would be
-9000x-36000
Answer:
$50
Step-by-step explanation:
Step one:
charges per hour= $60
We are told that the electrician earned $350
for a job that took 5hours
The linear equation to represent his earnings is
let the flat fee be x
C=60t+x------------1
so for C=$350
Required
the flat fee
350=60(5)+x
350=300+x
collect like terms
x=350-300
x=50
Flat fee is $50
