Answer:
When fluids (liquids and gases) are heated, they expand and therefore become less dense. Any object or substance that is less dense than a fluid will float in that fluid, so hot water rises (floats) in colder water.
Explanation:
When you heat up water, the water molecules start moving around faster and faster. ... So hot water is less dense than cold water. When you put the two together with the hot water on the bottom, the hot water rises to the top.
Please mark me as brainlist if it is helpful.
Answer:
Las técnicas moleculares, especialmente aquellas basadas en la manipulación del material genético, permitieron automatizar el proceso de identificación y clasificación de especies
Explanation:
Las técnicas moleculares usadas para la clasificación de organismos son aquellas principalmente relacionadas a la manipulación de su material genético. En especial, las técnicas de extracción de ADN, amplificación mediante la reacción en cadena de la polimerasa (PCR) y posterior secuenciación han posibilitado automatizar el proceso de clasificación de organismos. Los marcadores moleculares de ADN basados en secuencias génicas evolutivamente conservadas tales como, por ejemplo, la secuencia del gen Citocromo Oxidasa I (COI) en animales, son ampliamente usados para automatizar este proceso de identificación y clasificación de nuevas especies.
Answer:
I think this is the ans
Explanation:
cold environment as biodiversity means one particular ecosystem or habitat so in a cold environment only cold breeze flows.
<span><u>The answer is A. 72.25 percent.</u>
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1</em> and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of
the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq </em>are the
frequencies of the genotypes.
<span>The <em>r</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>R</em> allele frequency (<em>p</em>), the formula p + q = 1 is
used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>R</em> allele (<em>p</em>), it is easy to determine the
frequency of the RR genotype (p²):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
Answer:
D. Predator-prey!
Hope This Helps! And that I wasn't too late!