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3 years ago

Help me understand Lateral Area, and surface are pleassee

1 answer:

4 0

The lateral surface of an object is the area of all the sides of the object, excluding the area of its base and top. For a cube, the lateral surface area would be the area of four sides.For a pyramid, the lateral surface area is the sum of the areas of all of the triangular faces but excluding the area<span> of the base.</span>

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I just really need help with these 3 questions.

Oksanka [162]

For the 11 the first one is x = 4y and for the 2 one it will be x=−6−2y

8 0

3 years ago

Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6

Anton [14]

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

V= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder, $x^{2}+y^{2} =1$ and the ellipsoid, $4x^{2}+ 4y^{2} + z^{2} =64$

In polar coordinates, we know that

$x^{2}+y^{2} =r^{2}$

So, the ellipsoid gives

$4{(x^{2}+ y^{2)} + z^{2} =64$

4( $r^{2}$ ) + $z^{2}$ = 64

$z^{2}$ = 64- 4( $r^{2}$ )

z=± $\sqrt{64-4r^{2} }$

So, the volume of the solid is given by:

V= $\int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta$

= $2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta$

To solve the integral take, $64-4r^{2}$ = t

dt= -8rdr

rdr = $\frac{-1}{8} dt$

So, the integral $\int\ r\sqrt{64-4r^{2} } rdr$ become

= $\int\ \sqrt{t } \frac{-1}{8} dt$

= $\frac{-1}{12} t^{3/2}$

= $\frac{-1}{12} (64-4r^{2}) ^{3/2}$

so on applying the limit, the volume becomes

V= $2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta$

= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta$

V = $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Since, further the integral isn't having any term of $\theta$ .

we will end here.

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

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3 0

2 years ago

Use the gcf to create an equivalent expression 18y + 24

Virty [35]

Answer:

The gcf is 6.

we can divide by 6 on both sides to create

6(3y + 6)

Step-by-step explanation:

3 0

3 years ago

Pls find x will give brainliest

nasty-shy [4]

Answer:

Step-by-step explanation:

they are the same triangle look at corresponding sides. 9+9=18

3 0

4 years ago

Evaluate the expression 34 ÷ (14 − 5) × 2.

algol13

Answer:

$7\frac{5}{9}$

Step-by-step explanation:

Hi there!

We are given this expression:

34÷(14-5)×2

And we want to evaluate it

We'll be using the order of operations

Depending on the country you're in, the acronym can be different, but in the US, the typical acronym used for the order of operations is PEMDAS, or Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

The order of operations states that we should start with any expressions in parentheses

In this case, it's (14-5), which is equal to 9

The expression now becomes

34÷9×2

There are no exponents, so let's skip that

Now this is where it gets tricky:

Based on the acronym alone, we should be doing 9*2 next, however, we should always work left to right, even if in a case like this, we'll be doing division instead of multiplication

Divide 34 by 9

$\frac{34}{9}$ ×2

Now multiply $\frac{34}{9}$ by 2

$\frac{68}{9}$

(as a mixed fraction, it's 7 $\frac{5}{9}$ )

Hope this helps!

4 0

3 years ago