Ask question

Ask question

All categories

3 years ago

9

Use a geometric formula to solve the problem. a square has an area of 81 square meters. find the side length.

1 answer:

Yanka [14]3 years ago

4 0

Answer: 9 meters

To answer this question you need to know the formula to calculate the area of a square. Square has same side length so the area is: length x length.
Then the calculation would be:

Area= length x length
81m2= length x length
Length ^2= 81 m2
Lengtj= <span>√81 m2</span>
Length= 9 meters

You might be interested in

Which of the following is the most appropriate unit to describe the rate of the cost of gasoline?

malfutka [58]

Dollars per gallon because the dependent quantity is the dollars

Dollars is the dependent quantity because the amount you pay depends on how many gallons you've pumped.

3 0

3 years ago

Read 2 more answers

What is this symbol? and can someone please solve this algebra equation for me please?

omeli [17]

Well that symbol is an indention or multiply sign of expression

3 0

3 years ago

Read 2 more answers

Kelly is knitting a scarf for her brother in it to 1/3 hour to knit 3/4 foot of the scarf how fast is Kelly in knitting feet per

Naily [24]

I think the answer is 2.25 or 2 and 1/4.

You divide 3/4 by 1/3 and get 2.25 or 2 and 1/4.

I don't know if this is right, I hope it is, have a good day. c;

6 0

2 years ago

Help 3/4× 2 1/4 plsss

hammer [34]

Answer:

Step-by-step explanation:

3/4 x 9/4 = 1.6875 or 27/16

5 0

2 years ago

Read 2 more answers

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago