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Korolek [52]
3 years ago
8

Please help me please!!!!!

Mathematics
1 answer:
sattari [20]3 years ago
5 0
C 63 i guesses dude but can be 50 right or wrong
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On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
drek231 [11]

Answer:

  • B and E

Step-by-step explanation:

<u>Given</u>

  • ΔABC ⇒ A(- 1, 3), B(- 1, 1), C(3, 1)
  • ΔA'B'C' ⇒ A'(2, - 2), B'(2, - 4), C'(6, - 4)

<u>Comparing the coordinates of the corresponding vertices, we see the difference:</u>

  • x → x + 3, y →  y - 5

It means the ΔABC has been translated 3 units right and 5 units down

Correct answer choices are B and E

8 0
2 years ago
Read 2 more answers
3x+y=8________(1) and x²+xy=6________(2) solve this​
romanna [79]

Answer:

In first equation if we put the value of x and y (x=2,y=2)than,

3x+y=8

3×x+y=8

3×2+2=8

6+2=8

8=8

in second equation the value of x=2,y=1

x2+xy=6

x2+x×y=6

4+2×1=6

4+2=6

6=6

6 0
3 years ago
Read 2 more answers
(-9m+9) + (8m+8) simplify
lisabon 2012 [21]

Answer:

M+16m

Step-by-step explanation:

-9m+9 cancel eachother out because it is a negative and a postive value, so you would just put the variable. For 8m+8 it would be 16m because the sre both positive so you would add them like normal

7 0
2 years ago
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A cat is stuck in a tree looking down at firemen, the cat sat at a 20 degree angle
Svetach [21]

Answer:

BC=sin(62∘)⋅22≈19.42

8 0
2 years ago
Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th
STatiana [176]

We can find the acceleration via

{v_f}^2-{v_i}^2=2a\Delta x

We have

\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)

\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}

Then by definition of average acceleration,

a_{\rm ave}=\dfrac{v_f-v_i}t

so that

-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t

\implies\boxed{t=6.33\,\mathrm s}

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2

Then

\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2

\implies\boxed{t=6.33\,\mathrm s}

7 0
3 years ago
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