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3 years ago

PLEASE ANSWER ASAP!!!

Mathematics

2 answers:

den301095 [7]3 years ago

5 0

The volume of the figure is since you have to do width times heigh so 25 times 8 which would be 200 as your answer.

Natali5045456 [20]3 years ago

4 0

Answer:

The volume of the figure is since you have to do width times height so 25 times 8 which would be 200 as your answer.

Hope it helps

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Each year about 1500 students take the introductory statistics course at a large university. This year scores on the final exam

Luba_88 [7]

Answer:

a. Left Skewed

b. More students scored above 70

c. No

d. 0.0008

e. standard deviation increases by 1.4142

Step-by-step explanation:

a. The distribution is Left skewed. The maximum possible score is 100 and the mean is 70, hence, there is a barrier preventing a long right tail.

-The scores to the left is only 20, the left therefore is longer.

-The median, 74, is higher than the mean, 70, thus the mean is more left leaning.

b.More students will score more than 70.

-the median is 74 suggesting that 50% plus have scored 74points +

- Given the mean is 70 points, it's therefore obvious that more than 50% of the students have score more than 70 points.

c. No. This is not a normal distribution therefore we cannot calculate the probability that a randomly chosen student scored above 75 using this distribution.

d. The sample size n is large, n>30, so we can use the central limit theorem to approximate the probability:

$Standard \ Error=\frac{\sigma}{\sqrt{n}}\\\\=\frac{10}{\sqrt{40}}\\\\=1.5811\\\\z=\frac{75-70}{1.5811}\\\\=3.1623\\\\\\(PX>70)=P(z>3.1623)\\\\=0.0008\\$

e. The standard deviation will increase by the square root of the decreament :

$\sqrt{2}=1.4142$

#Standard deviation increases by 1.4142

3 0

3 years ago

The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula

ryzh [129]

Answer:

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

Step-by-step explanation:

We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.5 = 0.9$ , so $z = 1.282$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.282*\frac{6}{\sqrt{21}} = 1.68$

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.

The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

6 0

3 years ago

*PLEASE ANSWER PLS N TY * Which statement(s) are true about inscribed angles? Statement 1: The vertex of an inscribed angle lies

alex41 [277]

Answer:

c) 1 & 3 only

Step-by-step explanation:

In the picture attached, an example of an inscribed angle is shown.

In the example, the vertex is point B, which lies on the circle.

A chord of a circle is a straight line segment whose endpoints both lie on the circle, like segments BA and BC from the picture

4 0

4 years ago

Factorise 3x^3 - 12xy^2

igomit [66]

Answer:

we can conclude that:

$3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)$

Step-by-step explanation:

Given the expression

$3x^3-12xy^2$

Let us factorize the expression

$3x^3-12xy^2$

Apply the exponent rule: $a^{b+c}=a^ba^c$

$3x^3\:-\:12xy^2=3xx^2-12xy^2$

Rewrite 12 as 4 · 3

$=3xx^2-4\cdot \:3xy^2$

Factor out the common term 3x

$=3x\left(x^2-4y^2\right)$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=3x\left(x+2y\right)\left(x-2y\right)$

Therefore, we can conclude that:

$3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)$

8 0

3 years ago

As pointed out, you lose if the pile has 1, 6, 11 or 16 sticks. How many sticks are needed in the next two piles for you to lose

muminat

Answer:

21 and 26 totaling 47sticks

Step-by-step explanation:

Th number of sticks form an arithmetic progression

1, 6, 11, 16...

The nth term of an arithmetic progression is expressed as;

Tn = a+(n-1)d

a is the first term = 1

d is the common difference

d = 6-1 = 11-6 = 5

n is the number of terms

The next two terms are the fifth and sixth term

T5 = 1+(5-1)5

T5 = 1+4(5)

T5 = 1+20

T5 = 21

T6 = 1+(6-1)5

T6 = 1+5(5)

T6 = 1+25

T6 = 26

Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks

4 0

3 years ago