Answer:
32g - 38h
Step-by-step explanation:
Step 1:
14g - 8h - 30h + 18g
Step 2:
32g - 38h
Answer:
32g - 38h
Hope This Helps :)
X=212, y=88, n=50, L=212 hope this helps
This will be solved by solving for x first. Firstly you multiply the top equation by 2 and the bottom by -3. This will change both equation to (top)-10x+6y=-54 and (bottom) 27x-6y=-57. Now when you add the factors the y-values cancel out leaving you with; 17x=-3. now you have to divide by 17 on both sides giving you x=-0.17647058823 (not the prettiest solution but you can round if you want to). After that pick an equation to solve for y (I'm picking the top); the equation will be 5(-0.17647058823)+3y=-27. multiply the negative decimal and 5 to get -0.88235294117 (again not the prettiest). Add that to both sides which will give you 3y=-26.1176470588. After this divide both sides by 3 which will give you y=-8.70588235294. Your answer is (-0.17647058823,-8.70588235294) You can divide to the second or third decimal if needed-----remember that as you round from left to right on a decimal if it's below five you leave it and if it's above 5 then round up 1. I hope this help :)
Answer:
y(s) = 
we will compare the denominator to the form 

comparing coefficients of terms in s
1
s: -2a = -10
a = -2/-10
a = 1/5
constant: 

hence the first answers are:
a = 1/5 = 0.2
β = 5.09
Given that y(s) = 
we insert the values of a and β
= 
to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A
5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)
-52 = B(26)
B = -52/26 = -2
to get A lets substitute s=0.4
5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)
-51 = 0.2A - 52.08
0.2A = -51 + 52.08
A = -1.08/0.2 = 5.4
<em>the constants are</em>
<em>a = 0.2</em>
<em>β = 5.09</em>
<em>A = 5.4</em>
<em>B = -2</em>
<em></em>
Step-by-step explanation:
- since the denominator has a complex root we compare with the standard form

- Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
- substitute the values gotten into the function
- Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
- after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above
Thanks...