Answer: (B)
Explanation: If you are unsure about where to start, you could always plot some numbers down until you see a general pattern.
But a more intuitive way is to determine what happens during each transformation.
A regular y = |x| will have its vertex at the origin, because nothing is changed for a y = |x| graph. We have a ray that is reflected at the origin about the y-axis.
Now, let's explore the different transformations for an absolute value graph by taking a y = |x + h| graph.
What happens to the graph?
Well, we have shifted the graph -h units, just like a normal trigonometric, linear, or even parabolic graph. That is, we have shifted the graph h units to its negative side (to the left).
What about the y = |x| + h graph?
Well, like a parabola, we shift it h units upwards, and if h is negative, we shift it h units downwards.
So, if you understand what each transformation does, then you would be able to identify the changes in the shape's location.
The answer is 408. One way to solve is to do 8*50 and then do 8*1 and add the products together.
The required scale model will be 1:6.24 10^9
<h3>Finding scale factors</h3>
A scale factor is the ratio of the length of a side of one figure to the length of the corresponding side of the other figure.
Given the following parameters
Distance of sun to Jupiter = 7.8 * 10^8 km
If the distance of sun to Jupiter is 8m on his scale, hence the value of n is calculated as;
n = 8 * 7.8 *10^8
n = 62.4 * 1068
n = 6.24 10^9
Hence the required scale model will be 1:6.24 10^9
Learn more on scale model here: brainly.com/question/24105256
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Answer:
318 cm.
Step-by-step explanation:
Let x represent the distance between Bill and fulcrum.
We have been given that Laura has a mass of 60 kg and is sitting 265 cm from the fulcrum of a seesaw. Bill has a mass of 50 kg.
To balance the seesaw, the product of Laura's weight and her distance from fulcrum of seesaw should be equal to the product of Bill's weight and his distance from fulcrum of seesaw as:





Therefore, Billy should be 318 cm far from the fulcrum to balance the seesaw.