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tatiyna
3 years ago
7

What is the solution of (3x+8)/(x-4) greater than or equal to=0

Mathematics
2 answers:
svetlana [45]3 years ago
7 0

Answer:

x ≥ -8/3

Step-by-step explanation:

=> \frac{3x+8}{x-4} \geq 0

Multiplying both sides by (x-4)

=> 3x+8 ≥ 0

Subtracting 8 to both sides

=> 3x ≥ -8

Dividing both sides by 3

=> x ≥ -8/3

Levart [38]3 years ago
6 0

Answer:

x\le \:-\frac{8}{3}

x>4

Step-by-step explanation:

\frac{3x+8}{x-4}\ge \:0

Multiply both sides by (x - 4).

\frac{3x+8}{x-4} (x-4) \ge \:0(x-4)

3x+8\leq \:0

3x+8-8\leq \:0-8

3x \leq  \:-8

x\le \:-\frac{8}{3}

Makes denominator equal to 0.

x-4=0

x = 4

-8/3 \leq  x  doesn't work in the original inequality.

x>4  works in the original inequality.

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