Question

What is the solution of (3x+8)/(x-4) greater than or equal to=0

Answer 1

Answer:

x ≥ -8/3

Step-by-step explanation:

=> $\frac{3x+8}{x-4} \geq 0$

Multiplying both sides by (x-4)

=> 3x+8 ≥ 0

Subtracting 8 to both sides

=> 3x ≥ -8

Dividing both sides by 3

=> x ≥ -8/3

Answer 2

Answer:

$x\le \:-\frac{8}{3}$

$x>4$

Step-by-step explanation:

$\frac{3x+8}{x-4}\ge \:0$

Multiply both sides by (x - 4).

$\frac{3x+8}{x-4} (x-4) \ge \:0(x-4)$

$3x+8\leq \:0$

$3x+8-8\leq \:0-8$

$3x \leq \:-8$

$x\le \:-\frac{8}{3}$

Makes denominator equal to 0.

$x-4=0$

$x = 4$

$-8/3 \leq x$  doesn't work in the original inequality.

$x>4$  works in the original inequality.