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saul85 [17]
2 years ago
14

3ab+2 x -a =2c a=2 b=3 c=7 True or False

Mathematics
1 answer:
ollegr [7]2 years ago
8 0

Answer:

t

Step-by-step explanation:

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Which statement is true about the points shown on the number line?
Arlecino [84]
It should be "A"

On the number line, it shows that -4.5 is further and to the right of -2.3.

Hope that helps!
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Please‼️help me<br>Myanmar Grade7​
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5 0
2 years ago
How many solutions does the equation 9x-3(x+8)=6x-24
Marina86 [1]
Simplifying
9x + -3(x + 8) = 6x + -24

Reorder the terms:
9x + -3(8 + x) = 6x + -24
9x + (8 * -3 + x * -3) = 6x + -24
9x + (-24 + -3x) = 6x + -24

Reorder the terms:
-24 + 9x + -3x = 6x + -24

Combine like terms: 9x + -3x = 6x
-24 + 6x = 6x + -24

Reorder the terms:
-24 + 6x = -24 + 6x

Add '24' to each side of the equation.
-24 + 24 + 6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
0 + 6x = -24 + 24 + 6x
6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0
7 0
3 years ago
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Please help!!!! Chris is a fitness instructor.
dmitriy555 [2]

Answer:

i think its d

Step-by-step explanation:

3 0
3 years ago
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
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