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vladimir1956 [14]
3 years ago
8

Can three segments with lengths 8, 15, and 6 make a triangle?

Mathematics
1 answer:
butalik [34]3 years ago
5 0
Yes, not a equallateral but an issoceles

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In circle M, segment AB is tangent to the circle at point C. AB has endpoints such that AM BM  ,
iren2701 [21]

Answer:

6

Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is the radius CM and the segments are AC and BC.

CM = \sqrt{AC \times BC} = \sqrt{ 9 \times 4} = \sqrt{36} = \mathbf{6}\\\text{The radius of the circle M is $\large \boxed{\mathbf{6}}$}

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3 years ago
(HELP!) During her visit to zoo, lvy stops by the cafe and orders a chicken fajita taco and a juice. if she pays for her order w
grin007 [14]

Answer:

Step-by-step explanation:

Chicken fajita = 3.50

Juice = 1.50

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10-5=5

5 is the change that will be received

4 0
3 years ago
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Solve for y<br> 1/2y + 3/2 = 3y+4
denpristay [2]
The answer to 1/2y+3/2=3y+4 is y= -1
3 0
2 years ago
Four of the same textbooks contain a total of 848 pages. Which represents the total number of pages, y, of any number of the sam
Brilliant_brown [7]

Answer:

The best option is c

Step-by-step explanation:

The same textbooks contains a total of 848 pages . Which represent the total number of pages , y , of any number of the same textbooks , x.

The number of same text book = x

Each of this textbook contains a total of 848 pages .

The total number of pages can be computed as

y = 848x

for 4 same text book

y = 848 × 4 = 3392 pages

for 3 same text book

y = 848 × 3= 2544 pages

for 7 same text book

y = 848 × 7 = 5936 pages

for 8 same text book

y = 848 × 8 = 6784 pages

for 11 same text book

y = 848 × 11 = 9328 pages

3 0
3 years ago
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Helpppppp asapppppopoo
wlad13 [49]
Answer: Choice A

Raising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.

Rule:
x^{1/n} = \sqrt[n]{x}
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)
4 0
3 years ago
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