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ValentinkaMS [17]
4 years ago
10

From a group of 20 day workers and 12 night workers, a skeleton work crew of 5 day workers and 3 night workers must be formed. i

n how many ways can this be done
Mathematics
1 answer:
wel4 years ago
5 0

Answer:

3,410,880 ways.

Step-by-step explanation:

There are no markings to differentiate the position so the order is not important. The group also divided into day and night workers which independent from each other.

You want to make a schedule for 5 day workers out of 20 day workers, the number of ways to do that will be: 5C20= 20!/5!15! =15504 ways

You want to make a schedule for 3 night workers out of 12 night workers, the number of ways to do that will be: 3C12= 12!/3!9! =220 ways

The total number of ways possible will be 15504 * 220 = 3410880 ways.

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Find an equation of the plane. The plane that passes through the line of intersection of the planes x − z = 3 and y + 4z = 1 and
Nata [24]

Answer:

• 3x +y +z = 10

Step-by-step explanation:

The cross product of the normals of the intersecting planes will give a vector that is parallel to the line of intersection.

(1, 0 -1) × (0, 1, 4) = (1, -4, 1) . . . . using an appropriate calculator

Since this line is in the desired plane, it will be perpendicular to the desired plane's normal vector. The reference perpendicular plane likewise has its normal vector perpendicular to that of the desired plane. Hence the normal vector of the desired plane is perpendicular to both (1, -4, 1) and (1, 1, -4). It can be found from the cross product of these:

(1, -4, 1) × (1, 1, -4) = (15, 5, 5)

We can divide this by 5 to find our desired plane's normal vector: (3, 1, 1). To finish the equation of our plane, we need to know a point on the line of intersection. If we suppose z=0 at that point, then the remaining coordinates are ...

x -0 = 3 ⇒ x=3

y+4·0 = 1 ⇒ y=1

Using point (3, 1, 0) to find the constant in our plane's formula

3x +y +z = constant

we see it is ...

3·3 +1·1 +1·0 = constant = 10

The equation of the desired plane is ...

3x +y +z = 10

3 0
4 years ago
Can somebody help me with this please
miss Akunina [59]

Answer:

q=-14

Step-by-step explanation:

3 0
3 years ago
Solve for X in the figure below. Show your work. 22* Degrees 3x+11
Snowcat [4.5K]
Where’s the photo to this question?
7 0
3 years ago
1/4:1/6 = x:1/4<br><br> x=?
vodka [1.7K]

Answer:

1/6

Step-by-step explanation:

the distributive property one side has to equal the other

6 0
3 years ago
Find the maximum value of P=3x+2y subject to the following constraints:<br> Please help me!!!
UkoKoshka [18]

Answer:

maximum value of P is 33

Step-by-step explanation:

Sketch the lines represented by the constraints

5x + y = 16

with intercepts (\frac{16}{5}, 0) and (0, 16)

2x + 3y = 22

with intercepts (11, 0) and (0, \frac{22}{3})

The solutions to both are below the lines.

Solve 5x + y = 16 and 2x + 3y = 22 simultaneously to find the point of intersection at (2, 6)

The coordinates of the vertices of the feasible region are

(0, 0), (0, 16), (2, 6), 11, 0)

Evaluate the objective function at each vertex

P = 3(0) + 2(0) = 0 + 0 = 0

P = 3(0) + 2(16) = 0 + 32 = 32

P = 3(2) + 2(6) = 6 + 12 = 18

P = 3(11) + 2(0) = 33 + 0 = 33

The maximum value of P is 33 when x = 11 and y = 0

6 0
3 years ago
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