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JulijaS [17]
3 years ago
11

How do you solve this 2y/3-9= 2y+3

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

y= -5

Multiply both sides by 3

you get (2y−27=6y+9)

Subtract 2y from both sides

Simplify 6y+9−2y to 4y+9

Subtract 9 from both sides

Simplify −27−9 to −36

Divide both sides by 4

Simplify 36/4 to 9

Then switch the sides to get,

y= -9



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A restaurant owner was experimenting with the taste of her homestyle lemon drink. She started with 60 litres of water. She remov
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Answer:

ratio of pure lemon juice to water in the homestyle lemon  drink is 5 : 19.

Step-by-step explanation:

In order to solve the final ratio of lemon juice to water, let us start by determining the initial ratio of pure lemon juice to water in the first mix. This is done as follows:

Total volume of mixture = 60 liters

initial volume of water = 60 liters

initial volume of lemon juice = 0 liters

1) She removed 15 liters of the water and replaced it with 15 liters of pure lemon juice.

Volume of water = 60 - 15 = 45 liters

Volume of lemon juice = 15 liters

 \therefore \frac{15}{60}\ = \frac{1}{4}\  of\ the\ first\ mix\ is\ lemon\ juice\\\frac{45}{60}\ = \frac{3}{4}\  of\ the\ first\ mix\ is\ pure\ water

2) She removed 10 liters of the new mixture

Let us convert this amount removed into ratio:

lemon\ juice\ = \frac{1}{4}\ \times 10 = \frac{10}{4} = \frac{5}{2}\ liters.\\  \therefore the\ owner\ removes\ \frac{5}{2}\ liters\ of\ pure\ lemon\ juice\\pure\ water\ = \frac{3}{4}\ \times 10 = \frac{30}{4} = \frac{15}{2}\ liters\\  \therefore\ the\ owner\ removes\ \frac{15}{2}\ liters\ of\ water\ from\ the\ first\ mix.

New volumes of water and lemon juice after removing the 10 liters of mixture is calculated as follows:

lemon\ juice\ = 15 - \frac{5}{2} = \frac{30-5}{2} = \frac{25}{2}\ liters\ of\ lemon\ juice\\pure\ water\ = 45 - \frac{15}{2} = \frac{90-15}{2} = \frac{75}{2}\ liters\ of\ pure\ water

3) and replaced it with 10 liters of water.

New\ volume\ of\ water\ = 10 + \frac{75}{2} = \frac{20+ 75}{2} = \frac{95}{2}\ liters

The final ratio of lemon juice to water:

\frac{25}{2} : \frac{95}{2}\\= 25 : 95\\= 5 : 19

Therefore, the final ratio of pure lemon juice to water in the homestyle lemon  drink is 5 : 19.

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3 years ago
A bottle of shampoo was on sale for $6.45.
schepotkina [342]

Answer:

$7 for the first question

$6.50 for the last one

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3 years ago
Alexis was shopping on the ground floor of the mall when she realized she had left her phone in her car. She walks down 6 floors
expeople1 [14]

Answer:

-6

Step-by-step explanation:

-6 represents alexis position after she walks to her car.

the integer 0 represents the location of the ground floor!

hope this helped! <3

6 0
3 years ago
4. The distribution of blood cholesterol level in the population of young men aged 20 to 34 years is close to Normal, with mean
Pie

Answer:

a) 38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b) By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 188, \sigma = 41

a. Find the probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

This is 1 subtracted by the pvalue of Z when X = 200. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{200 - 188}{41}

Z = 0.29

Z = 0.29 has a pvalue of 0.6141

1 - 0.6141 = 0.3859

38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b. Suppose you measure the cholesterol level of 100 young men chosen at random and calculate the sample mean. If you did this many times, i. what would be the mean of the distribution of the sample mean

By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

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Working together, jo and ralph can do the garden chores in 6 hours. it takes jo twice as long as ralph to do the work alone. how
creativ13 [48]
Let's say Ralph can do the chores in h hours, and Jo in 2h. Then:
1/h+1/2h=1/6
6+3=h
h=9
Ralph takes 9 hours working alone; Jo takes 18 hours
☺☺☺☺
3 0
4 years ago
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