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JulijaS [17]
3 years ago
11

How do you solve this 2y/3-9= 2y+3

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

y= -5

Multiply both sides by 3

you get (2y−27=6y+9)

Subtract 2y from both sides

Simplify 6y+9−2y to 4y+9

Subtract 9 from both sides

Simplify −27−9 to −36

Divide both sides by 4

Simplify 36/4 to 9

Then switch the sides to get,

y= -9



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Answer:

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Step-by-step explanation:

First, you need to find the area of the lateral surfaces, since each one is a 5cm by 6cm rectangle, all you need to do is multiply to find the area of one of them, and then multiply by 6 to find the area of all 6 sides.

lateral area = 5cm * 6cm * 6

lateral area = 30cm² * 6

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Next, you need to find the total surface area by multiplying the area of the base by two and adding that to the lateral surface area.

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