Question

in a pea plant round seeds are dominant over wrinkled. A plant is homozygous dominant for round seeds is crossed with a heterozygous plant, what is the probability the offspring will have round seeds? out of 100 seeds, how many would you expect to be round?​

Answer 1

Answer:

100% probability, 100 out of 100

Explanation:

Homozygous dominant means that the plant has two alleles of the same dominant trait, in this case, round. Heterozygous plant means it has two different alleles, one round and one wrinkled. If you put them in a punnett square, you get two heterozygous and two homozygous dominant. All of them will get you a round pea plant since they all have the dominant trait in them. I can show you the punnett square I made.

Answer 2

Answer: The probability that the offspring will have round seed is 1. 100 of the offsprings will have round see, that is all the offsprings will have round seed.

Explanation: Let R represent the allele for round seed while r represent the allele for wrinkled seed. A homozygous dominant round seed plant will have a genotype of RR while a heterozygous plant will have a genotype of Rr. A cross between RR and Rr will produce 2RR and 2Rr. Since R is dominant to r, Rr will manifest outwardly as round seed, therefore all the offsprings will have round seeds.

See the punnett square below:

_ R R

R RR RR

r Rr Rr