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Ganezh [65]
4 years ago
10

[20 points+Brainliest] Solve the system of equations. Please give an explanation with your answer, please! A detailed answer wil

l get Brainliest. :)​

Mathematics
1 answer:
12345 [234]4 years ago
4 0

Answer:

  (x, y, z) = (3, 1, 2)

Step-by-step explanation:

Solving using a calculator, I would enter the coefficients of 1/x, 1/y, 1/z as they are given. The augmented matrix in that case looks like ...

\left[\begin{array}{ccc|c}\frac{1}{2}&\frac{1}{4}&-\frac{1}{3}&\frac{1}{4}\\1&-\frac{1}{3}&0&0\\1&-\frac{1}{5}&4&\frac{32}{15}\end{array}\right]

My calculator shows the solution to this set of equations to be ...

  • 1/x = 1/3
  • 1/y = 1
  • 1/z = 1/2

So, (x, y, z) = (3, 1, 2).

___

Doing this by hand, I might eliminate numerical fractions. Then the augmented matrix for equations in 1/x, 1/y, and 1/z would be ...

\left[\begin{array}{ccc|c}6&3&-4&3\\3&-1&0&0\\15&-3&60&32\end{array}\right]

Adding 3 times the second row to the first, and adding the first row to the third gives ...

\left[\begin{array}{ccc|c}15&0&-4&3\\3&-1&0&0\\21&0&56&35\end{array}\right]

Then adding 14 times the first row to the third, and dividing that result by 77 yields equations that are easily solved in a couple of additional steps.

\left[\begin{array}{ccc|c}6&3&-4&3\\3&-1&0&0\\3&0&0&1\end{array}\right]

The third row tells you 3/x = 1, or x=3.

Then the second row tells you 3/3 -1/y = 0, or y=1.

Finally, the first row tells you 15/3 -4/z = 3, or z=2.

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