All categories

3 years ago

The lines shown below are parallel.if the green line has a slope of -2,what is the slope of the red line?

2 answers:

6 0

The slope is -2.

When lines are parallel, the slopes of the lines will be equal to one another.
When lines are perpendicular they have negative reciprocal slopes, and the product of their slopes will equal -1.

ArbitrLikvidat [17]3 years ago

3 0

Answer:

-2

Step-by-step explanation:

If the lines are parallel, the slopes are the same.

Since the green line has a slope of -2, the red line has a slope of -2

You might be interested in

Please Help!!

RUDIKE [14]

1000 grams

1kg = 1 liter

so also 1000 ml

8 0

3 years ago

Read 2 more answers

Find the highest common factor (HCF) of 72 and 98.

Y_Kistochka [10]

Answer:

2

Step-by-step explanation:

The factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The factors of 98: 1, 2, 7, 14, 49, 98

Your greatest common factor is 2.

Hope this helps. Have a nice day.

3 0

3 years ago

Can someone please help me fill in the answer in the bottom.

Julli [10]

Answer:

Step-by-step explanation:

1) Initial water level = 30 feet

2) Rate of change = (30 - 25) / (0 - 1) = 5/(-1) = -5

5ft per hour

3) y-intercept = 30

6 0

3 years ago

Read 2 more answers

Write an algebraic expression that represent the sum of 8 and two-third of x?

lesantik [10]

We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,

thus, the expression is

$\frac{2}{3}x+8$

3 0

1 year ago

Find the variance of this probability distribution. Round to two decimal places.

attashe74 [19]

Answer:

Variance = 4.68

Step-by-step explanation:

The formula for the variance is:

$\sigma^{2} =\frac{\Sigma(X- \mu)^{2}}{N} \\or \\ \sigma^{2} =\frac{\Sigma(X)^{2}}{N} -\mu^{2} \\$

Where:

$X: Values \\\mu: Mean \\N: Number\ of\ values$

The mean can be calculated as each value multiplied by its probability

$\mu = 0*0.4 + 1*0.3 + 2*0.1+3*0.15+ 4*0.05=1.15$

$\frac{\Sigma (X)^{2}}{N} =\frac{(0^{2}+1^{2}+2^{2}+3^{2}+4^{2})}{5} =6$

Replacing the mean and the summatory of X:

$\sigma^{2} = \frac{\Sigma(X)^{2}}{N} -\mu^{2} \\= 6 - 1.15^{2}\\= 4.6775$

4 0

4 years ago