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2 years ago

Three consecutive integers have a sum of 56. what are the three integers

Mathematics

1 answer:

denis23 [38]2 years ago

8 0

Answer:

impossible

Step-by-step explanation:

X + X + 1 + X + 2 = 56. To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. ...

3X + 3 = 56. 3X + 3 - 3 = 56 - 3.

3X = 53. 3X/3 = 53/3.

X = 17 2/3. Since 17 2/3 is not an integer, there is no true answer to this problem.

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Step-by-step explanation:

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2 years ago

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Reika [66]

Answer:

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Step-by-step explanation:

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0$

$\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}$

$\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}$

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