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2 years ago

Find the area of the court

Mathematics

1 answer:

Romashka [77]2 years ago

8 0

Answer:

7.4. I BELIEVE...sorry if i did it wrong

Step-by-step explanation:

1 2/3 + 1 2/3 = 3.33333333

2 + 2 = 4

3.333333 + 4 = 7.333333

7.333333 rounded would be 7.4

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Can someone help me please

UNO [17]

The interior angles are 3, 4, and 6. Angle 3 is adjacent to angle 1, so is not remote.

The remote interior angles to angle 1 are

... A. angle 4

... E. angle 6

5 0

2 years ago

Please answer correctly! I will mark you as Brainleist!

kiruha [24]

Answer:

V ≈ 1847.26

Step-by-step explanation:

<u>Circular Cone Formulas in terms of radius r and height h:</u>

The volume of a cone:

V = (1/3)πr2h

Slant height of a cone:

s = √(r2 + h2)

Lateral surface area of a cone:

L = πrs = πr√(r2 + h2)

The base surface area of a cone (a circle):

B = πr2

The total surface area of a cone:

A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

Therefore, the solution V = πr 2h / 3 = π·142·9/ 3 ≈ 1847.25648

4 0

3 years ago

One side of a shipping container measures 8 feet. The container is a cube. What is the container's volume in cubic feet?

DerKrebs [107]

Answer:c

Step-by-step explanation:

3 0

3 years ago

Compute the measures of center for both the boys and girls data. Describe their differences. Use the terms mean and median to ju

polet [3.4K]

Answer:boys: median=50, mean=46

Girls: median= 33, mean=34

Step-by-step explanation:

Mean is the average. Median is the middle number. Both groups had 10 scores. Boys ranged from 15-81. Girls from 0-75; their mean & median would be less because their scores are less.

6 0

3 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago

Find the area of the court​

Find the area of the court