18 is the right answer. The two fractions must be porportional
Answer:
he has 10 type of each coin
Step-by-step explanation:
Total number of cents in possession is calculated as;
= 25 + 10 + 5
= 40 cent
Total amount in possession = $4
= 400 cent
Since he has equal number of each cent, let this equal number be "y";
40cent (y) = 400cent
40y = 400
divide both sides by 40

Therefore, he has 10 type of each coin
Answer:
46/ 67
Step-by-step explanation:
The numbers of students irrespective of grades is;
The sum of the last roll of numbers:
10+24+ 33+ 67 = 134
The number of males irrespective of grades is the sum of the numbers in the male row ;
7 +20+ 14 +41= 82
The numbers of students with grade A is the first column at the last row and is 10;
Hence;
the probability that the student was male OR got an 'A' is
the probability that the student was male plus the probability that he/she got an 'A'.
The probability that it's a male is ;
Number of males/ total number of students
=82/134
The probability that he got an A is;
The number of students that got A/ the total number of students;
10/134
Hence
the probability that the student was male OR got an 'A' is;
82/ 134 + 10/134 = 92/134 = 46/ 67
Good morning ☕️
Answer:

Step-by-step explanation:
the line passes through the points (1 , 2) and (7 , 7)
then

____________
:)
Let's assume m represent the mileage of the car.
Given that, Primo car rental agency charges $33 per day plus $0.20 per mile.
So, the total charge for this agency = 33 + 0.20m.
Similarly total charge of the ultimo car = 17 + 0.85m.
Now we need to find the daily mileage for which the ultimo charge is four times the primo charge . So, we can set up an equation as following:
17 + 0.85m = 4 *( 33 + 0.20m )
17 + 0.85m = 132 + 0.80m By distribution property.
17 + 0.85m -0.80m = 132 + 0.80m -0.80m Subtract 0.80m from each sides.
17 + 0.05m = 132
17 + 0.05m - 17 = 132 - 17 Subtract 17 from each sides.
0.05m = 115
Divide each by 0.05.
So, m = 2300
Hence, the daily mileage is 2300 miles.
Hope this helps you!