Find the 31st term of the following sequence. 9, 15, 21, ...
1 answer:
Notice that the above sequence is arithmetic because the common difference: d is constant.
d = second term - first term.
= 15 - 9
= 6
The general term of an arithmetic sequence is,
a_{n} =a_{1} +(n-1)d
Where , nth term =
= First term
and d = common difference.
The given sequence is: 9, 15, 21, ...
Here a_{1} = 9,
d = 6
We need to find the 31st term. So, n = 31.
Next step is to plug in these values in the above formula. Therefore,
= 9 + 30* 6
= 9 + 180
= 189
So, 31st term of this sequence is 189.
Hope this helps you.
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Answer:
0.5
Step-by-step explanation:
The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)
The corresponding sequence is :
2,2.5,3,3.5, 4,....
We can see that there is a common difference of d=0.5.
Better still we could use the slope formula:
We substitute the point (1,2) and (2,2.5).
The rate of change of this sequence is: