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densk [106]
3 years ago
10

Find the 31st term of the following sequence. 9, 15, 21, ...

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0

Notice that the above sequence is arithmetic because the common difference: d is constant.

d = second term - first term.

= 15 - 9

= 6

The general term of an arithmetic sequence is,

a_{n} =a_{1} +(n-1)d

Where , nth term = a_{n}

a_{1} = First term

and d = common difference.

The given sequence is: 9, 15, 21, ...

Here a_{1} = 9,

d = 6

We need to find the 31st term. So, n = 31.

Next step is to plug in these values in the above formula. Therefore,

a_{31} =9 +(31-1)*6

= 9 + 30* 6

= 9 + 180

= 189

So, 31st term of this sequence is 189.

Hope this helps you.

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Y=1/2x-1
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Answer:

<h2>Y=1/2x-1</h2>

Find where the expression

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x=1/2

Consider the rational function

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1. If n<m, then the x-axis, y=0, is the horizontal asymptote.

2. If n=m, then the horizontal asymptote is the line y = ab.

3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).

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There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

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<h2>2x+y=4</h2>

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Rewrite in slope-intercept form.

The slope-intercept form is

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y=mx+b

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Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y

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Create a table of the x and y values.

x y

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Graph the line using the slope and the y-intercept, or the points.

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Step-by-step explanation:

Hope it is helpful...

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