What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?

Mathematics

1 answer:

LiRa [457]3 years ago

8 0

Answer:

3865.74 J/s

Step-by-step explanation:

mass of ice, m = 1 ton = 1000 kg

time , t = 24 hours

latent heat of fusion of ice, L = 334000 J/kg

Heat required to melt, H = m x L

where, m is the mass of ice and L be the latent heat of fusion

So, H = 1000 x 334000 = 334 xx 10^6 J

Rate of heat transfer = heat / time = $\frac{334\times 10^{6}}{86400}$

Rate of heat transfer = 3865.74 J/s

thus, the rate of heat transfer is 3865.74 J/s.

You might be interested in

1. If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?

Ad libitum [116K]

A) If 9 students sharpen 18 pencils in 2 minutes,Then if the time is halved, it will take twice as many men to sharpen 18 pencils.Hence it will take 18 students to sharpen 18 pencils in one minute B) y & 1/x. Then y = K/x where K is our constant of proportionality.Then K = yx. When x = -64 and y = -16 then K = -64 * -16 = 1024. Option DC) When x = 3 y = 8. So for an inverse variation K as calculated from B = 3 * 8 = 24.Then when K = 24 and y = 6; we have 24 = 6x. Hence x = 4. Option A

6 0

3 years ago

The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t

lions [1.4K]

I got 81 members. 4 x 20 = 80 81-80=1
6 x 13= 78 81-78= 3
7 x 11= 77 81-77= 4

6 0

3 years ago

Which number line shows the solution set for |a|=6?

ivann1987 [24]

Answer:

the third one

Step-by-step explanation: