What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?
1 answer:
Answer:
3865.74 J/s
Step-by-step explanation:
mass of ice, m = 1 ton = 1000 kg
time , t = 24 hours
latent heat of fusion of ice, L = 334000 J/kg
Heat required to melt, H = m x L
where, m is the mass of ice and L be the latent heat of fusion
So, H = 1000 x 334000 = 334 xx 10^6 J
Rate of heat transfer = heat / time =
Rate of heat transfer = 3865.74 J/s
thus, the rate of heat transfer is 3865.74 J/s.
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B. (0.85 0.15)
C. 79.2% population in the city while 20.8% population in the suburb
Step-by-step explanation:
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C S
(b) the probability vector for the information is
and this gives us
(0.85 0.15)
(c) we simply multiply the above two matrices to find the percent of the population can be expected to be in each category after one year after
in the city there are 79.2% while in the suburb, there are 20.8%