Ask question

Ask question

All categories

3 years ago

15

A bike wheel. The weight of a full steel bead tire is approximately 800 grams, while a lighter wheel weighs only 700 grams. What

is the weight of each tire in pounds? There are 453.592 grams in one pound. Round answers to 2 decimal places. 800 grams = pounds 700 grams = pounds

2 answers:

steposvetlana [31]3 years ago

4 0

Answer:

1.76

pounds

1.54

pounds

Step-by-step explanation:

got it right

AleksandrR [38]3 years ago

3 0

Answer:

a. 800 grams = 1.76 pounds

b. 700 grams = 1.54 pounds

Step-by-step explanation:

Here is a weight conversion problem.

In this question, we shall be making conversions from grams to pounds.

Kindly note that 453.592 grams = 1 pound as stated in the question

a. 800 grams

Kindly recall;

453.592 grams = 1 pound

800 grams = x pound

Thus;

453.592 * x = 800 * 1

x = 800/453.592

x = 1.764 pounds which is 1.76 pounds to 2 decimal places

b. 700 grams

1 pound = 453.592 grams

y pound = 700 grams

y * 453.592 = 700 * 1

y = 700/453.592

y = 1.543 pounds which is 1.54 to 2 decimal places

You might be interested in

Consider the computer output below. Fill in the missing information. Round your answers to two decimal places (e.g. 98.76). Test

slamgirl [31]

Answer:

$SE_{Mean}=\frac{s}{\sqrt{n}}=\frac{4.77}{\sqrt{19}}=1.094$

$t=\frac{98.77-100}{\frac{4.77}{\sqrt{19}}}=-1.124$

The 95% confidence interval would be given by (96.625;100.915)

a) $df=n-1= 19-1= 18$

b) $p_v =2*P(t_{18}$

If we compare the p value and a significance level for example $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

c) The only thing that changes is the p value and would be given by:

$p_v =P(t_{18}>-1.124)=0.862$

But again since the p value is higher than the significance level we fail to reject the null hypothesis.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

$\bar X=98.77$ represent the sample mean

$s=4.77$ represent the sample standard deviation

n=19 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if we have significant difference on the mean of 100, the system of hypothesis would be:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we can calculate the Standard error for the mean like this:

$SE_{Mean}=\frac{s}{\sqrt{n}}=\frac{4.77}{\sqrt{19}}=1.094$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$98.77-1.96\frac{4.77}{\sqrt{19}}=96.625$

$98.77+1.96\frac{4.77}{\sqrt{19}}=100.915$

So on this case the 95% confidence interval would be given by (96.625;100.915)

Part a

The degree of freedom are given by:

$df=n-1= 19-1= 18$

Part b

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{98.77-100}{\frac{4.77}{\sqrt{19}}}=-1.124$

Then since is a two sided test the p value would be:

$p_v =2*P(t_{18}$

If we compare the p value and a significance level for example $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Part c

If the system of hypothesis on this case are:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu > 100$

The only thing that changes is the p value and would be given by:

$p_v =P(t_{18}>-1.124)=0.862$

But again since the p value is higher than the significance level we fail to reject the null hypothesis.

7 0

3 years ago

6) Carpeting costs $9.99 a yard. If Jan buys 17.4 yards, how much will it cost here (Round your answer

kogti [31]

This is the answer

Hope it helped

4 0

3 years ago

Read 2 more answers

Express the following fraction in simplest form using only positive exponents.<br><br> 4j^7/5(j^2)3

Damm [24]

Answer djdjdjdnd is 263838339

5 0

3 years ago

For a project on Egypt, Nick is building a paper model of a square based pyramid. The square base measures 8 inches by 8 inches.

gladu [14]

Answer:

Step-by-step explanation:

The square base measures 8 inches by 8 inches. The slant height is 10 inches.

The formula for determining the area of the square base of the pyramid is l^2. Therefore,

Area of the base = 8^2 = 64 inches^2

The formula for determining the perimeter of the square base is

4l. It becomes

4 × 8 = 32 inches

The amount of construction paper needed to make this pyramid is the total surface area of the pyramid. Therefore,

Total surface area = (1/2 × 32 × 10) + 64

= 160 + 64 = 224 inches^2

5 0

3 years ago

The exponential model A=831.1 e^0.022t describes the population,A, of a country in millions, t years after 2003. Use the model t

KIM [24]

Answer:

831.1 million

Step-by-step explanation:

If the exponential model describes the population after 2003 and we must determine the population of the country in 2003 then t=0 because the time only starts after 2003:

$A=831.1\cdot{e^(0.022\cdot{0})}$

e to the power of 0 is equal to 1:

$A=831.1\cdot{e^(0.022\cdot{0})}=831.1\cdot{1}=831.1$

The population in 2003 is 831.1 million

8 0

3 years ago