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Gwar [14]
3 years ago
12

In how many different, distinguishable orders can the letters of the word mathematics be arranged?

Mathematics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

B)4,989,600

Step-by-step explanation:

The letters of 'MATHEMATICS'  contains 11 letters.

The following letters repeats twice, TT,MM,AA.

When we talk of distinguishable wasy, we are referring to arrangement without repetition.

Therefore the letters of "MATHEMATICS" can be arranged in \frac{11!}{2!2!2!}=4,989,600 distinguishable ways.

The correct answer is B.

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Igoryamba
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3 years ago
Upper Deck $9.25
Elena-2011 [213]

Answer:

13

Step-by-step explanation:

Purchase 2 upper deck tickets:

\$100-(2*\$9.25)=\$81.50

You can then buy 13 right field bleacher tickets before you reach deficit:

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Because you cannot purchase a .583 of a ticket, the most you can buy is 13.

8 0
3 years ago
Read 2 more answers
8 friends share 3 cookies, what fraction of the cookie does each friend get?
kirza4 [7]
8 friends share 3 cookies.

There are 3 cookies and 8 people.

We need to know how much cookie 1 friend gets.

1 friend gets 3/8 of a cookie.

There are 8 friends, so 8 x 3/8 = 3. The 8 friends will finish 3 cookies if they all have 3/8 of a cookie.

Each friend gets 3/8 of a cookie.
4 0
3 years ago
The length of a rectangle is twice the with. If the perimeter of the rectangle is 60 units, find the area of the garden
Darya [45]

w - width

2w - length

60 - perimeter

w + w + 2w + 2w = 6w - perimeter

The equation:

6w = 60    <em>divide both sides by 6</em>

w = 10 → 2w = 2 · 10 = 20

The area: A = width × length

A = (10)(20) = 200

<h3>Answer: The area of the garden is equal 200 square units.</h3>
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2 years ago
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kompoz [17]

Answer:

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Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

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3 years ago
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