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creativ13 [48]
3 years ago
9

Which values are solutions to the inequality below? Check all that apply.x2  25

Mathematics
1 answer:
lawyer [7]3 years ago
3 0
B D and E
Hdhdhsmsndnsndnnsjsbdndndndhdjdndndhf
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A ) The angle formed by 2 consecutive radii:
Ф= 360° : 8 = 45°
b ) The angle formed by a radius and a side of a polygon:
α = (180° - 45°): 2 = 135° : 2 = 67.5°
Answer:
B ) 45°, 67.5°
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3 years ago
A=bx+cx+d solve for x
BigorU [14]
(a/bc) - d = x is the answer
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A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

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3 years ago
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Alisiya [41]

Answer:

B,7

Step-by-step explanation:

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3 years ago
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Josh has 212 marbles. Peck has 314 marbles. Round each number to the nearest hundred. Then, type how much marbles more does Peck
Taya2010 [7]

Round each number to the nearest hundred.

 212 = 200.

 314 = 300.

How much more marbles does Peck have?

 314 - 212 = 102.

That is your answer. Hope this helps!

5 0
3 years ago
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