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4 years ago

What's the answer for this maths question ?

Mathematics

1 answer:

Zarrin [17]4 years ago

6 0

$x \geqslant 2$
This implies that x is greater than or equal to 2. Which means that x is 2,3,4,5,6,7,8......

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A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approx

puteri [66]

The answer is around 168.56

work :

the side of the square is 28 in

so the diameter of the circle is 28 in, too(look at the picture)

then the radius is 14 (28/2)

the area of the circle is
$(14 \times 14) \times 3.14 = 615.44$

the area of the square is
${28}^{2} = 784$

so the area of the shaded region will be around:
$784 - 615.44 = 168.56$

good luck

6 0

3 years ago

Read 2 more answers

A tailor has 641 yards of material to make costumes. Each costume needs 3 yards of material. How many costumes can be made? Will

Arturiano [62]

641/3= 213 costumes with .666 leftover

3 0

4 years ago

Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report

Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M± $\frac{t*s}{\sqrt{N}}$ where

M is the average track length (12 μm) in the report
t is the two tailed t-score in 99% confidence interval (2.977)
s is the standard deviation of track lengths in the report (2 μm)
N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12± $\frac{2.977*2}{\sqrt{15}}$ =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0

3 years ago

A trumpet has a length of 140cm. The first valve lowers the root note by two semitones (f1/f0 = 2-2/12) and the second valve low

Alexxandr [17]

Answer:

a. 17.145cm

b. 8.325cm

c. 0.846

d. 2.896

Step-by-step explanation:

It is known that frequency is inversely proportional to length.

Case 1: The player presses only the first valve.

f₁/fo = 2^{-2/12} = lo/l₁

given that lo= 140cm.

l₁ = 2^{2/12}lo = 157.145

change in length:

l₁ - lo = 157.145 - 140 = 17.145cm

Case 2: The player presses only the second valve.

f₂/fo = 2^{-1/12} = lo/l₂

l₂ = 2^{1/12}lo = 148.325cm

l₂ - lo= 148.325-140 = 8.325cm

Case 3: The player presses both the first and second valve.

Change in length is the sum of change in length when they are individually pressed.

l₃ - lo = 17.145+8.325 = 25.47cm

l₃ = 25.47cm+lo = 165.47cm

f₃/fo = 2^{-n/12} = lo/l₃

f₃/fo = 2^{-n/12} = 140/{165.47 = 0.846

2^{-n/12} = 0.846\Rightarrow n/12 = -log(0.846)/log(2) = 0.2413

n = 0.2413*12 = 2.896

5 0

3 years ago

Which of these expressions shows a correct way to set up the slope formula for the line that passes through the points (3, 7) an

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

option c is correct

6 0

3 years ago