Answer:
(3, 5)
Step-by-step explanation:
Answer:
y = mx + b
Step-by-step explanation:
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :

Distance of P from ( -3, 4 ) :

Now , these distance are equal :

Solving above equation , we get :

Hence , this is the required solution.